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blondinia [14]
3 years ago
12

Ayúdame hacer este ejercicio: -10÷(-2)

Mathematics
2 answers:
Alexeev081 [22]3 years ago
7 0
La respuesta de el ejercicio es 5
Marizza181 [45]3 years ago
3 0
-10/-2= 5. Es Cinco(5)
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You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week
bonufazy [111]

Answer:

a) The demand function is

q(p) = -4 p + 107

b) The nightly revenue is

R(p) = -4 p^2 + 107 p

c) The profit function is

P(p) = -4 p^2 + 133.75 p - 939

d) The entrance fees that allow Swing Haven to break even are between 10.03 and 23.41 dollars per guest.

Step-by-step explanation:

a) Lets find the slope s of the demand:

s = \frac{79-43}{7-16} = \frac{36}{-9} = -4

Since the demand takes the value 79 in 7, then

q(p) = -4 (p-7) + 79 = -4 p + 107

b) The nightly revenue can be found by multiplying q by p

R(p) = p*q(p) = p*( -4 p + 107) = -4 p^2 + 107 p

c) The profit function is obtained from substracting the const function C(p) from the revenue function R(p)

P(p) = R(p) - C(p) = p*q(p) = -4 p^2 + 107 p - (-26.75p + 939) = \\\\-4 p^2 + 133.75 p - 939

d) Lets find out the zeros and positive interval of P. Since P is a quadratic function with negative main coefficient, then it should have a maximum at the vertex, and between the roots (if any), the function should be positive. Therefore, we just need to find the zeros of P

r_1, r_2 = \frac{-133.75 \,^+_-\, \sqrt{133.75^2-4*(-4)*(-939)} }{-8} = \frac{-133.75 \,^+_-\, 53.526}{-8} \\r_1 = 10.03\\r_2 = 23.41

Therefore, the entrance fees that allow Swing Haven to break even are between 10.03 and 23.41 dollars per guest.

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The function described f(x) = B + Cx
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2 years ago
ms green tell you that a right triangle has a hypotenuse of 13 and a leg of 5 . She asks you to find the other leg of the triang
Montano1993 [528]

Answer:

\large \boxed{12}

Step-by-step explanation:

We can apply Pythagoras' Theorem.

\begin{array}{rcc}a^{2} & = & b^{2} + c^{2}\\13^{2}& = & 5^{2} + c^{2}\\169& = & 25 + c^{2}\\c^{2}& = & 144\\c & = & \sqrt{144}\\& = & \mathbf{12}\\\end{array}\\\text{The other leg of the triangle is $\large \boxed{\mathbf{12}}$}

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3 years ago
Over a 24-hour period, the tide in a harbor can be modeled by one period of a sinusoidal function. The tide measures 4.35 ft at
netineya [11]

Answer:

  f(x) = 4.35 +3.95·sin(πx/12)

Step-by-step explanation:

For problems of this sort, a sine function is used that is of the form ...

  f(x) = A + Bsin(2πx/P)

where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.

It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...

  f(x) = 4.35 + 3.95·sin(2πx/24)

The argument of the sine function can be simplified to πx/12, as in the Answer, above.

8 0
3 years ago
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