Answer:
Erwin have 1
gallons of lemonade left
Step-by-step explanation:
<u><em>Erwin had 2 5/12 gallons of lemonade. He spilled 11/12 gallon of lemonade. How much lemonade dose he have left? Write in simplest form</em></u>
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All we need to do is to subtract 11/12 from 2 5/12. But to do this, we will convert 2 5/12 to improper fraction
converting 2 5/12 to improper fraction yields : 29/12
Lemonade have left = Total lemonade - lemonade spilled
= 29/12 - 11/12
= 18/12
Lemonade have left =18/12
But we can reduce 18/12 to its lowest term
18÷6/ 12÷6 = 3/2
Lemonade have left = 3/2
We can change to 3/2 to a mixed number to give us 1
Therefore Erwin have 1
gallons of lemonade left
Step-by-step explanation:
23. area of rect,r = 11 x 3.5 = 38.5cmsq
area of tri, t = 6 x3.5/2 = 10.5 cmsq
area of shaded region, sr = r-t
=> sr = 38.5- 10.5 = 28.5cmsq
24. area of square, s = 10x10 = 100mmsq
area of circle, c = pi x 5^2 = 78.5mmsq
area of shaded region, sr = s - c
=> sr = 100- 78.5 = 22.5mmsq
25. area of circle, c = pi x 6^2 = 113.04insq
area of tri, t = 6x12/2 = 36insq
area of shaded region, sr = c - t
=> sr = 113.04 - 36 = 77.04insq
Answer:
Radius: 8.5 inches
Area ≈ 226.98
Circumference ≈ 53.42
Step-by-step explanation:
2πr = formula for circumference of a circle
πr² = formula for area of a circle
radius of a circle = (1/2)d
Answer:
The number of Jack's stamps is 33 and Dylan's stamps is 13
Step-by-step explanation:
Let
x -----> the number of Jack's stamps
y -----> the number of Dylan's stamps
we know that
x+y=46 ----> equation A
x=y+20 -----> equation B
Solve by substitution
substitute equation B in equation A and solve for y
(y+20)+y=46
2y=46-20
2y=26
y=13 stamps
Fond the value of x
x=y+20 -----> x=13+20=33 stamps
therefore
The number of Jack's stamps is 33 and Dylan's stamps is 13
Answer:
18
Step-by-step explanation:
45-27=18