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Oksi-84 [34.3K]
3 years ago
11

1 QUESTION. PLEASE HELP. VOLUME GEOMETRY QUESTION.

Mathematics
1 answer:
mina [271]3 years ago
3 0
Knowing the volume of a 3-D shape is extremely when deciding what materials to use and how much of them to use.  When you know the volume of the different designs is helpful when deciding which material costs less to use but still meets requirements. For example, if you were trying to decide what material to fill your product with, and say the volume of your product is 36^3. You narrow things down to two products, one costing $54 to fill the entire thing. The other costing $60. Because you have the volume, it will be easy to decide which is better based off of the price per square inch. If you didn't have the volume. You would have to make an estimate and potentially make a bad business decision.   

Hope this helps! I apologize for my long response
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-5 -(15y - 1) = 2(7y - 16) -y
Luda [366]
-5-(15y-1) = 2(7y-16) - y  // question
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-15y - 4 = 13y - 32    // subtract
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y = 1
7 0
4 years ago
if a circle of radius 2 is made to roll along the x-axis, what is an equation for the path of the center of the circle?
Blizzard [7]
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7 0
3 years ago
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How do I find the percentile of someone with a certain number of things from a dot plot data set?
dalvyx [7]

Answer:

percentile rank of x =

number of values before x                           100

---------------------------------------------------  x    ----------

number of total values on the dot plot         1

Step-by-step explanation:

you divide the number of values before x over the number of total values on the dot plot, and divide the quotient by 100 to get your percentile.

5 0
3 years ago
What is the answer to 16-2t = t + 9 + 4t <br><br>I need it now
bogdanovich [222]

16 - 2t = t + 9 + 4t

16 - 2t = 5t + 9

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5 0
3 years ago
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Which of the following is an equation for the plane through the point (1, 1, −1) and parallel
Bas_tet [7]

The given plane, x-y+z=3, has normal vector \vec n = \langle1,-1,1\rangle. Any plane parallel to this one has the same normal vector.

Let (x,y,z) be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

\langle x,y,z\rangle - \langle 1,1,-1\rangle = \langle x-1, y-1, z+1 \rangle

and this is perpendicular to \vec n.

So the equation of the plane is

\langle x-1, y-1, z+1 \rangle \cdot \vec n = 0 \implies (x-1) - (y-1) + (z+1) = 0 \implies \boxed{x - y + z = -1}

or equivalently,

\boxed{-x + y - z = 1}

6 0
2 years ago
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