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3 years ago

Wha is the nth term of 2 5 8 11 14

1 answer:

5 0

If you look at the sequence, you would observe:

5 - 2 = 3, 8 - 5 = 3, 11 - 8 = 3.

There is a common difference of 3, so the sequence is an Arithmetic Progression.

nth term of an AP = a + (n - 1)d

where a = 1st term = 2, d = common difference = 3

nth term of an AP = a + (n - 1)d

nth term of an AP = 2 + (n - 1)*3 = 2 + 3*n - 3*1 = 2 + 3n - 3

= 2 - 3 + 3n

= -1 + 3n

= 3n - 1

The nth term = 3n - 1, where n = 1, 2, 3, 4, 5,....

I hope this explains it.

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Given that (6,-8) is on the graph for f(x), find the corresponding point for the function f(x+1)

Sever21 [200]

Answer: ( 5, -8)

Step-by-step explanation:

3 0

3 years ago

The scale from a square park to a drawing of the park is 5 miles to 1 miles. The actual park has an area of 1,600 m×2 what is th

Flauer [41]

The user corrected that the scale of a drawing of a park reads: 5 miles to 1 cm , and we know that the park measures 1,600 square meters (user insisted that this measure is given in square meters and not square miles).

So we have to convert the 1600 square meters into miles, knowing that 1 meter is the same as: 0.000621371 miles

then meters square will be equivalents to:

1 m^2 = (0.000621371 mi)^2

then 1600 m^2 = 0.00061776 mi^2

now, since 5 miles are represented by 1 cm, then 25 square miles will be represented by 1 square cm

and therefore 0.00061776 square miles will be the equivalent to:

0.00061776 / 25 cm^2 = 0.000024710 cm^2

So and incredibly small number of square cm.

I still believe that some of the information you gave me are not in meters but in miles. (For example, the park may not be in square meters but in squared miles). The park seems to have the size of a house according to the info.

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1 year ago

Which side lengths below DO NOT produce a right triangle?

tresset_1 [31]

C 3*3 = 9 6*6=36 and 36 plus 9 is 45 and 9*9 = 81 so it’s not equal and not right.

3 0

3 years ago

Read 2 more answers

Fibonacci posed the following problem: Suppose that rabbits live forever and that every month each pair produces a new pair whic

docker41 [41]

Answer:

Let f_n be the number of rabbit pairs at the beginning of each month. We start with one pair, that is f_1 = 1. After one month the rabbits still do not produce a new pair, which means f_2 = 1. After two months a new born pair appears, that is f_3 = 2, and so on. Let now n $\geq$ 3 be any natural number. We have that f_n is equal to the previous amount of pairs f_n-1 plus the amount of new born pairs. The last amount is f_n-2, since any two month younger pair produced its first baby pair. Finally we have

f_1 = f_2 = 1,f_n = f_n-1 + f_n-2 for any natural n $\geq$ 3.

5 0

3 years ago

According to postal regulations, a carton is classified as "oversized" if the sum of its height and girth (the perimeter of its

Amanda [17]

Answer:

V(max) = 8712.07 in³

Dimensions:

x (side of the square base) = 16.33 in

girth = 65.32 in

height = 32.67 in

Step-by-step explanation:

Let

x = side of the square base

h = the height of the postal

Then according to problem statement we have:

girth = 4*x (perimeter of the base)

and

4* x + h = 98 (at the most) so h = 98 - 4x (1)

Then

V = x²*h

V = x²* ( 98 - 4x)

V(x) = 98*x² - 4x³

Taking dervatives (both menbers of the equation we have:

V´(x) = 196 x - 12 x² ⇒ V´(x) = 0

196x - 12x² = 0 first root of the equation x = 0

Then 196 -12x = 0 12x = 196 x = 196/12

x = 16,33 in ⇒ girth = 4 * (16.33) ⇒ girth = 65.32 in

and from equation (1)

y = 98 - 4x ⇒ y = 98 -4 (16,33)

y = 32.67 in

and maximun volume of a carton V is

V(max) = (16,33)²* 32,67

V(max) = 8712.07 in³

3 0

3 years ago