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qaws [65]
3 years ago
13

How do you divide can someone plz tell me

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0
Just divide
Like 4:2=2
charle [14.2K]3 years ago
5 0
Its pretty easy lets say 2:4 How many times does 2 go into 4 two times see easy
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Y - 5 = -2x - 4<br><br>Write in simpilest form.
Romashka-Z-Leto [24]
Y - 5 = -2x - 4

Add 5 on both sides.
y = -2x + 1

y = -2x + 1 is in simplest form.
7 0
4 years ago
Does f(x) mean ftimes x when referring to a functionſ? if not, what does f(x) mean? Provide an example with your explanation,​
sattari [20]

Answer:

f(x) - when referring to a function - means that x is the input value that you substitute into an equation.

For example, if f(x) = 2x + 3 and you were asked to find f(2), you could substitute x = 2 into the equation 2x + 3 to get 7.

Hope this helps!

6 0
2 years ago
1 + 200000 - 1 + 200000
Valentin [98]
1+200000-1+200000
200001-1+200000
200000+200000
400000
4 0
3 years ago
I need help AND DON'T SAY IDK TO GET POINTS ITS NOT RIGHT
ANEK [815]

Answer:

y = x + 2

y = 2x

y = x + 5

y = 0.5x

Step-by-step explanation:

For the first three, I don't know how to explain this to you. This is very simple math, I am certain that you would have been able to do this in two minutes if you applied yourself. It would be much faster if you did the work yourself and only used brainly for things that you truly don't understand.

For the fourth answer, consider:

x is miles per 60 minutes.

y is miles per 30 minutes.

30 is half of 60, or 0.5 times 60.

Therefore, y will be equal to 0.5 times x.

y = 0.5x.

3 0
3 years ago
Consider the function f(x) = √5x + 15 for the domain [-3, ∞).Find f-¹(x), where f-1 is the inverse of f.Also state the domain of
Ymorist [56]

Answer: We have to find the inverse function of the following:

f(x)=\sqrt{5x+15}\rightarrow[-3,\infty)\Rightarrow(1)

The Inverse of the (1) is as follows:

\begin{gathered} f(x)=y=\sqrt{5x+15} \\  \\ \text{ Switch: }x\text{  and }y\text{ and solve for }y(x)\text{ } \\  \\  \\ y=\sqrt{5x+15}\rightarrow x=\sqrt{5y+15} \\  \\  \\ x^2=5y+15 \\  \\  \\ x^2-15=5y \\  \\  \\ y=\frac{x^2}{5}-\frac{15}{5} \\  \\  \\  \\ y=f^{-1}(x)=\frac{x^2}{5}-3 \\  \\  \\ f^{-1}(x)=\frac{x^{2}}{5}-3 \end{gathered}

The domain of the inverse function is:

x\in(-\infty,+\infty)

3 0
1 year ago
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