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balu736 [363]
3 years ago
12

Draw the organic product formed when the structure shown below undergoes a reaction with nanh2. there is no aqueous workup in th

is reaction.

Chemistry
1 answer:
blagie [28]3 years ago
5 0

Answer:

Prop-1-yn-1-ide

Explanation:

In this case, we will have an <u>acidic hydrogen</u> upon the left carbon in the alkyne. In the presence of a<u> base</u>, we can <u>remove</u> this hydrogen. In this reaction the base will be NH_2^-. The <u>amidure ion</u> will remove the hydrogen of the alkyne to produce a <u>carboanion</u>. (See figure)

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What is the concentration of HNO3 if 9.80×10−2 mol are present in 705 mL of the solution?
nydimaria [60]

Answer:

The answer to your question is 0.13 M

Explanation:

Data

[HNO₃] = ?

moles of HNO₃ = 9.8 x 10⁻²

volume = 705 ml

Process

1.- Convert volume to milliliters

                 1000 ml ------------------ 1 L

                    705 ml ------------------ x

                    x = (705 x 1) / 1000

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3 years ago
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<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
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