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Natasha2012 [34]
2 years ago
14

Why is melting ice a physical change?

Chemistry
2 answers:
Zepler [3.9K]2 years ago
8 0

Answer:

Explanation:

1. or .4

Snowcat [4.5K]2 years ago
4 0
I say, it moves into a permanent place
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A student wishes to calculate the experimental value of Ksp for AgI. S/he follows the procedure in Part 3 and finds Ecell to be
Ymorist [56]

Answer:

a)    [Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)    1.273 × 10⁻¹⁶

c)    2.629×10⁻¹⁹ M Thus; the value for  [Ag+ ]dilute will be too low

Explanation:

In an Ag | Ag+ concentration cell ,

The  anode reaction can be written as :

Ag ----> Ag+(dilute) + e-    &:

The  cathode reaction can be written as:

Ag+(concentrated) + e- ----> Ag

The  Overall Reaction : is

Ag+(concentrated) -----> Ag+(dilute)

However, the Standard Reduction potential of cell = E°cell = 0

( since both cathode and anode have same Ag+║Ag )

Also , given that the theoretical slope is - 0.0591 V

Therefore; the reduction potential of cell ; i.e

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

0.839 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 14.1963  

[Ag+]dilute = \mathbf{10^{-14.1963} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 6.363  × 10⁻¹⁶ M  

b)

AgI ----> Ag + (dilute) + I⁻

So , Solubility product = Ksp = [Ag⁺]dilute × [I⁻]  

= 6.363 × 10⁻¹⁶ M × 0.20 M  

= 1.273 × 10⁻¹⁶

c) If s/he mistakenly uses 1.039 V as Ecell; then the value for [Ag+]dilute will be :

Ecell = E°cell - 0.0591 V × log ( [Ag+]dilute / [Ag+]concentrated )

1.039 V = 0 - 0.0591 V × log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) )  

log ( [Ag+]dilute / ( 1.0 × 10⁻¹ M ) ) = - 17.5804  

[Ag+]dilute = \mathbf{10^{-17.5804} } × 1.0 × 10⁻¹ M

[Ag+]dilute = 2.629×10⁻¹⁹ M

Thus, the value for  [Ag+ ]dilute will be too low

5 0
3 years ago
Which of the following pieces of information about the element lithium describes the atomic number only
vagabundo [1.1K]
The top left corner shows the atomic number which is 3.
6 0
3 years ago
How does energy from Earth’s interior affect surface changes?
quester [9]

Answer:

Energy produced deep inside Earth heats rock in the mantle. ... As it becomes less dense, the heated rock rises toward Earth's surface. The cooler, denser rock surrounding the heated rock sinks, as Figure 5 shows. In this way, heat inside Earth moves toward the cooler crust.

Explanation:

do you like my og name

5 0
2 years ago
Read 2 more answers
Group 7A (17) elements can gain one electron to attain a noble gas electron configuration. In combination with metal atoms that
Iteru [2.4K]

Answer:

The two statements are all True for group 7 and 8 elements.

Explanation:

The Group 7 elements are known as the halogens. They are reactive non-metals and are always found in compounds with other elements. Chlorine, bromine and iodine are all halogens.

Chlorine, bromine and iodine are the three common Group 7 elements. Group 7 elements form salts when they react with metals. The term ‘halogen’ means 'salt former'.

In addition to the discription given to norble gases in the question which is true, norble gases;

  •     are inert gases located on the right of the periodic table.
  •     have a full-set of valence electrons, so they're stable, unreactive
  •     are colorless, odorless and tasteless.
  •     have low melting and low boiling points.
  •     can be found in small amounts in the Earth's crust and the Earth's atmosphere.
5 0
3 years ago
The [H+] of a solution can be determined from the pH using the equation: [H+] = 10 - pH ... Where: [H+] = hydrogen ion concentra
padilas [110]

Answer:

pH = -log₁₀ [H⁺]

Explanation:

pH is a value in chemistry used in to measure solution trying to determine each quality, purity, risks for health of some products, etc.

As you write in the question, [H⁺] = 10^(-pH)

Using logarithm law (log (m^(p) = p log(m):

log₁₀ [H⁺] = -pH

And

<h3>pH = -log₁₀ [H⁺]</h3>
8 0
3 years ago
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