All categories

3 years ago

Find cos x if sin x cot x = 0.5

Mathematics

1 answer:

vova2212 [387]3 years ago

7 0

Answer:

cos x = 0.5

Step-by-step explanation:

cot x = (cos x) / (sin x)

sin x (cot x) = 0.5

cos x = 0.5

You might be interested in

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

Planes X and Y are perpendicular. Points A, E, F, and G are points only in plane X. Points R and S are points in both planes X a

NemiM [27]

Given:

Planes X and Y are perpendicular to each other
Points A, E, F, and G are points only in plane X
Points R and S are points in both planes X and Y
Lines EA and FG are parallel

The lines which could be perpendicular to RS are EA and FG.

6 0

3 years ago

Read 2 more answers

Please help!

UkoKoshka [18]

The values of x in the triangles and the angles in the rhombus are illustrations of tangent ratios

The values of x in the triangles are 21.4 units, 58 degrees and 66 degrees
The angles in the rhombus are 44 and 46 degrees, respectively

<h3>How to determine the values of x?</h3>

<u>Triangle 1</u>

The value of x is calculated using the following tangent ratio

tan(25) = 10/x

Make x the subject

x = 10/tan(25)

Evaluate

x = 21.4

<u>Triangle 2</u>

The value of x is calculated using the following tangent ratio

tan(x) = 8/5

Evaluate the quotient

tan(x) = 1.6

Take the arc tan of both sides

x = arctan(1.6)

Evaluate

x = 58

<u>Triangle 3</u>

The value of x is calculated using the following tangent ratio

tan(x) = 0.34/0.15

Evaluate the quotient

tan(x) = 2.27

Take the arc tan of both sides

x = arctan(2.27)

Evaluate

x = 66

<h3>How to calculate the angles of the rhombus?</h3>

The lengths of the diagonals are:

L1 = 2 in

L2 = 5 in

Represent the angles with x and y.

The measures of the angles are calculated using the following tangent ratios

tan(0.5x) = 2/5 and y = 90 - x

Evaluate the quotient

tan(0.5x) = 0.4

Take the arc tan of both sides

0.5x = arctan(0.4)

Evaluate

0.5x = 22

Divide by 0.5

x = 44

Recall that:

y = 90 - x

This gives

y = 90 - 44

Evaluate

y = 46

Hence, the angles in the rhombus are 44 and 46 degrees, respectively