25/27 = 0.925925925...
It's almost equal to 1 and it turns out that 1 is 100%.
So, we'd say that it's equal to:
92.59% (to 2 decimal places)
We've multiplied the value above (25/27) by 100.
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer:
156ft of material.
Step-by-step explanation:
Since the garden path borders the garden and is 3 feet wide, it increases the side lengths of his garden by 3 feet on each side. Then we just find the perimeter using the new values:

If this helped, a brainliest answer would be greatly appreciated!
Answer:
14.3 km
Step-by-step explanation:
Using the paths shown, we would need to add the path length from Belmont to Yardley and Yardley to Oxford. When we add 8.5 and 5.8, we get 14.3 km.
Hence,
the distance from Belmont to Oxford is 14.3 km.
Hope this helps!!! PLZ MARK BRAINLIEST!!!