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kherson [118]
3 years ago
10

Factor 6x2 + 12x - 9 completely.

Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

work is pictured and shown

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25 out of 27 as a percentage
Basile [38]
25/27 = 0.925925925...

It's almost equal to 1 and it turns out that 1 is 100%.

So, we'd say that it's equal to:

92.59% (to 2 decimal places)

We've multiplied the value above (25/27) by 100.
8 0
3 years ago
Read 2 more answers
G = 1, h = 2<br><br> 7 + g − 8 + 2h + 4g
Slav-nsk [51]

Answer:

7+1-8+2(2)+4(1)

= -1+4+4

=7

5 0
2 years ago
An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th
antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c  ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200 \times a + 100 \times c = 2100

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

<h3>c = 5</h3>

Thus the cost of children’s ticket is $ 5

6 0
3 years ago
Only people who know the answer
polet [3.4K]

Answer:

156ft of material.

Step-by-step explanation:

Since the garden path borders the garden and is 3 feet wide, it increases the side lengths of his garden by 3 feet on each side. Then we just find the perimeter using the new values:

P=36+36+42+42=156

If this helped, a brainliest answer would be greatly appreciated!

5 0
2 years ago
Please answer this correctly without making mistakes
andrew-mc [135]

Answer:

14.3 km

Step-by-step explanation:

Using the paths shown, we would need to add the path length from Belmont to Yardley and Yardley to Oxford. When we add 8.5 and 5.8, we get 14.3 km.

Hence,

the distance from Belmont to Oxford is 14.3 km.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

3 0
3 years ago
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