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irina [24]
3 years ago
7

Do number 7 and 8 please

Mathematics
1 answer:
Kruka [31]3 years ago
5 0

7) \sqrt[3]{64} = \sqrt[3]{4^3} = 4

8) \sqrt[3]{216} = \sqrt[3]{6^3} = 6

You might be interested in
Refer to Expression 1 and Expression 2.
TiliK225 [7]

Expression 1 is 25

6*7-3^2*9+4^3

First simplify all the exponents to get 6*7 - 9 * 9 + 64 and then multiply the two numbers to get 42 - 81 + 64 and just add = 25

For expression 2, if you put the parantheses around (5+4)*2+6-2*2-1, it'll be 19

(5+4)*2+6-2*2-1

9*2+6-2*2-1

18+6-4-1

24-5

19

Remember order of operations

5 0
3 years ago
X/-3-41=-11 show work please
Brilliant_brown [7]

The correct answer is x = -90.

To find this, solve using the order of operations. See the example below.

x/-3 - 41 = -11 ----> Add 41 to both sides

x/-3 = 30 ----> Multiply each side by -3

x = -90

4 0
3 years ago
A _____ is owned by its depositors who are paid dividends after all operating costs and fees are paid
pentagon [3]
The correct answer should be tax
5 0
3 years ago
Tom was driving 20.3 meters per second in a 45 mile per hour zone. Was Tom speeding? Explain using a unit conversion as well as
My name is Ann [436]

Answer:

Tom was speeding.

Step-by-step explanation:

The driving speed of Tom = 20.3 meters per second.

Speed allowed in the zone = 45 miles per hour zone.

Since the unit of speed allowed is given in miles per hour but the speed of tom is given in meters per second. So, first, we have to convert the meter per second into mile per hour then we can compare and find that Tom is speeding or not.  

1 mile = 1609.34 meters

1 hour = 3600 second

Now convert 20.3 into mile per hour.

20.3 meters per second. = (20.3 / 1609.34)*3600 = 45.40981 mile per hour.

Since Tom’s speed is more than the allowed speed so he is speeding.

7 0
3 years ago
H(t)= (t+3)^2 + 5
oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

\frac{h(-1)-h(-5)}{-1+5}

so we find:

h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9

then the average rate of change becomes:

\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0

5 0
3 years ago
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