It would be -22....,,...,,...,..
Answer:
0.25
Step-by-step explanation:
Given that a recently married couple are planning to have four children. They are equally likely to have a boy as well as a girl.
Let X be the no of boys the couples have. X has two outcomes with p = 0.5
X is binomial with n = no of trials = 4 and p =0.5
the probability that they will have three boys and one girl
=
Reqd prob = 0.25
Answer:
y = -2/3x+3
Step-by-step explanation:
Slope = y2-y1/x2-x1
(3,1) = (x1,y1)
(9,-3) = (x2,y2)
Slope = (-3-1)/(9-3)
= -4/6
= -2/3
y-intercept form: y=mx+b [m=slope, b=y-intercept]
plugging (3,1) into this 1 = -2/3×3 +b
1 = -2 +b
b = 3
Game
Using these variables, we can set up equations.
3x + 5y = 42
9x + 7y = 72
We have here a system of equations, where we have two or more equations with two or more different variables. We use the elimination method to solve for the variables.
Multiply eq1 by 3. Keep eq2.
9x + 15y = 126 eq1
9x + 7y = 72 eq2
Subtract eq2 from eq1 to eliminate the x terms.
8y = 54
y = 6.75
5,10,15,20,25,30 that is 1,2,3,4,5,6 6 of 100 is 18
