When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.
In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be
or, in interval notation,
![(-\infty,-2]\cup (1,\infty)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C-2%5D%5Ccup%20%281%2C%5Cinfty%29)
In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.
This means that the difference between your numbers at 1 must be at most 4, which is modelled by
where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.
Answer:
Area of big rectangle= 5m× 3m
= 15m²
Area of small rectangle=1m× 1m
=1m²
Area of shaded part= Area of big rectangle- Area of a small rectangle
= 15m²-1m²
= 14m²
Step-by-step explanation: Hope it helps
Step-by-step explanation:
If the parabola has the form
(vertex form)
then its vertex is located at the point (h, k). Therefore, the vertex of the parabola
is located at the point (8, 6).
To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is
where 
is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is
By definition, the length of the latus rectum is four times the focal length so therefore, its value is
Answer
Find the volume of the coin is cubic millimeters.
To prove
Formula
Where r is the radius and h is the height .
As given
The $1 coin depicts Sacagawea and her infant son.
The diameter of the coin is 26.5 mm, and the thickness is 2.00 mm.
Radius = 13.25 mm
Put in the formula
Volume of coin = 3.14 × 13.25 × 13.25 × 2.00
= 1102.53 mm³ (approx)
Therefore the volume of the coin is 1102.53 mm³ .
