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Oxana [17]
3 years ago
14

1 + 69 - (6x+4) x 2 = ?

Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0

Answer is: -12x + 62

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-12 divided by 3 x (-8 +(-4)^2 - 6) + 2
son4ous [18]

Answer:

this is the correct graph

8 0
2 years ago
What is the least common denominator for 13/108 and 23/233
Karo-lina-s [1.5K]
The first one stays the same as it does not simplify =108

and the second one is the sames as it does not simplify =233
6 0
3 years ago
Which property of equality would you use to solve the equation 14x=56
Oliga [24]
Okay so divide 56 by 14 and so x = 4
4 0
3 years ago
Two functions are defined as shown.
maxonik [38]

Answer:

Graph (2).

Step-by-step explanation:

Given question is incomplete: Find the complete question in the attachment.

Given : f(x) = -\frac{1}{2}x-2

            g(x) = - 1

To find : The graph showing f(x) = g(x)

If the given functions f(x) = g(x)

-\frac{1}{2}x-2=-1

-\frac{1}{2}x=-1+2

-\frac{1}{2}x = 1

x = -2

That means both the functions have the same value at x = -2

f(-2) = g(-2) = -1

In other words, both the lines will intersect at a point (-2, -1).

From the given graphs,

Graph number (2) shows the required results.

A straight line g(x) = -1 parallel to x- axis and another straight line f(x) = -\frac{1}{2}x-2, intersect each other at (-2, -1).

Therefore, Graph (2) will be the answer.

7 0
3 years ago
Read 2 more answers
A quadrilateral is shown on the graph below. If the dimensions of this
creativ13 [48]

Answer:

Area of the image rectangle = 4(Area of the original rectangle)

Step-by-step explanation:

Length of the rectangle given in the graph = 4 units

Width of the rectangle = 2 units

Area of the rectangle = Length × Width

                                    = 4 × 2

                                    = 8  square units

Since, scale factor = \frac{\text{Dimension of the image}}{\text{Dimension of the original}}

2 = \frac{\text{Length of the image}}{\text{Length of the original}}

Length of the image rectangle = 2(4)

                                                   = 8 units

Similarly, width of the image rectangle = 2(2)

                                                     = 4 units

Area of the image rectangle = 8 × 4

Area of the image = Area of the original × 4

Area of the image = 4(Area of the original)

Area of the image rectangle = 4(Area of the original rectangle)

5 0
2 years ago
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