Question

For an angle (theta) with the point (5, -12) on its terminating side, what is the value of cosine?

Answer 1

we are given

(x,y)=(5,-12)

so, x=5 and y=-12

now, we can find r

$r=\sqrt{x^2+y^2}$

$r=\sqrt{5^2+(-12)^2}$

$r=13$

now, we can find cos

$cos(\theta)=\frac{x}{r}$

so, we get

$cos(\theta)=\frac{5}{13}$...........Answer