I am not 100% sure but my answer would be parallel to the direction of the wave motion.
Answer:
A star with 15 solar masses is too big to be a main-sequence star.
The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m.
What is the de Broglie wavelength:
It is the wavelength that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.
A particle's de Broglie wavelength is usually inversely proportional to its force.
The formula of de Broglie wavelength:
here mass of a tennis ball is given
mass, m=70 g = 0.07 kg
ball is moving with velocity
v = 10 m/s
h is Plank constant,
h=6.63×10^(-34) Js
substituting the values in formula,
λ = 6.63×10^(-34) / ( 0.070*10)
λ = 9.4 ×10^(-34) m
Hence
The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m
Learn more about de Broglie wavelength here:
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As we know that acceleration due to gravity is given by

here we know that
g = 3.60 m/s^2
M = ?

now we have


so above is the mass of Mars
Answer:
i =
, i = 0.92 A
Explanation:
This exercise asks for the electromotive force, which can be calculated with Faraday's law
fem =
where the magnetic flux
Ф = B. A
bold letters indicate vectors. We can write this equation
Ф = B A cos θ
In this case the magnetic field is perpendicular to the page and the normal to the loop of the loop is also parallel to the page, therefore the angle is zero and the cosine is 1
the loop is
A = π r²
we substitute in the first equation
fem = - π r²
we substitute the values
fem = -π r² 1
fem = - π r²
to calculate the current let's use ohm's law
V = i R
R = ρ L / A'
where A 'is the area of the wire and L is the length of the loop
L = 2π r
V = i (ρ 2π r / A ')
I =
In this case
V = fem
I = fem / R
i =
In order to complete the calculation, you need the radius of the loop and / or the wire cutter.
if we assume that the loop has a radius of r = 1 cm = 0.01 m and an area of the wire A'= π 10⁻⁶ m² a radius of the wire 1 mm
i = - 10⁻² π 10⁻⁶ / ( 2 1.7 10-8)
i = 0.92 A