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jok3333 [9.3K]
4 years ago
11

A 62.2 kg ice skater moving to the right with a velocity of 2.66 m/s throws a 0.145 kg snowball to the right with a velocity of

39.3 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball? Disregard the friction between the skates and the ice.
Physics
1 answer:
Travka [436]4 years ago
3 0

Answer:

Velocity of skater after throwing the snowball is 2.57 m/s

Explanation:

Given :

Mass of skater, M = 62.2 kg

Mass of snowball, m = 0.145 kg

Velocity of snowball relative to ground, v = 39.3 m/s

Consider v₁ be the velocity of skater after throwing the snowball.

According to the problem, initially the velocity of skater and snowball is same. So,

Velocity of skater before throwing snowball, u = 2.66 m/s

Applying conservation of momentum,

Momentum before throwing snowball = Momentum after throwing snowball

(M + m) u = Mv₁ + mv

v_{1}=\frac{(M+m)u-mv}{M}

Substitute the suitable values in the above equation.

v_{1}=\frac{(62.2+0.145)2.66-0.145\times39.3}{62.2}

v₁ = 2.57 m/s

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Answer:

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What is the approximate de Broglie wavelength of a tennis ball with a mass of 70 g and a velocity of 10 m/s
dybincka [34]

The approximate de Broglie wavelength of a tennis ball is 9.4×10^(-34) m.

What is the de Broglie wavelength:

It is the wavelength that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.

A particle's de Broglie wavelength is usually inversely proportional to its force.

The formula of de Broglie wavelength:

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here mass of a tennis ball is given

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Learn more about de Broglie wavelength here:

<u>brainly.com/question/17295250</u>

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2 years ago
The acceleration due to gravity on Mars is 3.60 m/s2. if this is measured at a distance of 3.4 x 10^6 m from the center of the p
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here we know that

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GarryVolchara [31]

Answer:

     i =- \frac{r \ A'}{2 \ rho} ,  i =  0.92   A

Explanation:

This exercise asks for the electromotive force, which can be calculated with Faraday's law

          fem = - \frac{d \Phi_B }{dt}

where the magnetic flux

          Ф = B. A

bold letters indicate vectors. We can write this equation

          Ф = B A cos θ

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the loop is

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we substitute in the first equation

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