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UNO [17]
3 years ago
5

You discover a binary star system in which one member is a 15 solar mass main-sequence star and the other star is a 10 solar mas

s giant star. Why should you be surprised, at least at first
Physics
1 answer:
Sever21 [200]3 years ago
4 0

Answer:

A star with 15 solar masses is too big to be a main-sequence star.

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Friction _____.
quester [9]

Answer:

all above

Explanation:

friction is necessary to live

8 0
2 years ago
When the pendulum bob reaches the mean position, the net force acting on it is zero. Why then does it swing past the mean positi
ryzh [129]

Answer:

<u>The pendulum bob swing past the mean position because:</u>

When a pendulum's bob is accelerating at its extreme position its velocity is zero. Due to  the restoring toque the bob starts to accelerates towards its mean postion. The  maximum acceleration of the pendulum's bob  is -w^{2} Aand the the acceleration decreases as -w^{2} x  towards the mean position.

The acceleration at the mean position becomes zero but the velocity remains maximum. Hence the bob continues to move and does not stops.Thus it can summarised as the force decreases ,acceleration decreases and velocity increases at slow rate.

6 0
3 years ago
Find the potential energy of a 2 kg ball 15 m in the air.
mart [117]

Answer:

294.3 Joules

Explanation:

2kg*9.81m/s^2*Δ15=294.3J

8 0
3 years ago
A softball has a (positive/negative) acceleration when it is thrown. A soft ball has a (positive/negative) acceleration when it
Nadusha1986 [10]

Answer

A softball has a (negative) acceleration when it is thrown. A soft ball has a (positive) acceleration when it is caughtExplanation:

8 0
3 years ago
The wave function of a particle is exp(i(kx-omegat)), where x is distance, t is time, and k and co are positive real numbers. Th
Step2247 [10]

Answer:

Momentum, p=\hbar k

Explanation:

The wave function of a particle is given by :

y=exp[i(kx-\omega t)]...............(1)

Where

x is the distance travelled

t is the time taken

k is the propagation constant

\omega is the angular frequency

The relation between the momentum and wavelength is given by :

p=\dfrac{h}{\lambda}............(2)

From equation (1),

k=\dfrac{2\pi}{\lambda}

\lambda=\dfrac{2\pi}{k}

Use above equation in equation (2) as :

p=\dfrac{h k}{2\pi }

Since, \dfrac{h}{2\pi}=\hbar

p=\hbar k

So, the x-component of the momentum of the particle is \hbar k. Hence, this is the required solution.

8 0
3 years ago
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