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strojnjashka [21]
3 years ago
6

If a device uses mains electricity at 230v and has a 13a fuse in the plug wht is the maximmum power it can safley use?

Physics
1 answer:
Harman [31]3 years ago
5 0

Answer:

2990W

Explanation:

Given parameters:

Voltage  = 230V

Current = 13A

Unknown:

Maximum power it can safely use  = ?

Solution:

To solve this problem;

       Power  = Current  x Voltage

     Power  = 230 x 13  = 2990W

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Susan, driving north at 53 mphmph , and Shawn, driving east at 63 mphmph , are approaching an intersection. Part A What is Shawn
mafiozo [28]

Answer:

Shawn's speed relative to Susan's speed = 10 mph

Resultant velocity = 82.32 mph

Explanation:

The given data :-

i) Susan driving in north and speed of Susan is ( v₁ ) = 53 mph.

ii) Shawn driving in east and speed of Shawn is ( v₂ ) = 63 mph.

iii) The speed of both Susan and Shawn is relative to earth.

iv) The angle between Susan in north and Shawn in east is 90°.

We have to find Shawn's speed relative to Susan's speed.

v₂₁ = v₂ - v₁   = 63 - 53 = 10 mph

Resultant velocity,

v = \sqrt{v_{2} ^{2}+ v_{1} ^{2}  }  =\sqrt{63^{2} +53^{2} }

v = 82.32 mph

5 0
4 years ago
A car travels along a straight road to the east for
Korvikt [17]

Answer: 90 m/s, 70 m/s

Explanation:

Given

A car travels 100 m  east for 4 seconds and then turn around

goes back west for 50m  in 1 sec

Distance traveled in the east is 100\times 4=400\ m

Distance traveled in the west is 50\times 1=50\ m

Total distance=400+50=450\ m

total displacement=400-50=350\ m

total time t=4+1=5\ s

Average speed

\Rightarrow s_{avg}=\dfrac{\text{distance}}{\text{time}}=\dfrac{450}{5}\\\\\Rightarrow s_{avg}=90\ m/s

Average velocity

\Rightarrow v_{avg}=\dfrac{\text{displacement}}{\text{time}}=\dfrac{350}{5}\\\\\Rightarrow v_{avg}=70\ m/s

6 0
3 years ago
Given that the mass of the Earth is 5.972 * 10^24 kg and the radius of the Earth is
Pachacha [2.7K]

Answer:

gₓ = 6.52 m/s²

Explanation:

The value of acceleration due to gravity on the surface of earth is given as:

g = GM/R²   -------------------- equation 1

where,

g = acceleration due to gravity on surface of earth

G = Universal Gravitational Constant

M = Mass of Earth

R = Radius of Earth

Now, for the alien planet:

gₓ = GMₓ/Rₓ²

where,

gₓ = acceleration due to gravity at the surface of alien planet

Mₓ = Mass of Alien Planet = 2.4 M

Rₓ = Radius of Alien Planet = 1.9 R

Therefore,

gₓ = G(2.4 M)/(1.9 R)²

gₓ = 0.66 GM/R²

using equation 1

gₓ = 0.66 g

gₓ = (0.66)(9.81 m/s²)

<u>gₓ = 6.52 m/s²</u>

3 0
3 years ago
Which sentence from the article supports the idea that the visible spectrum is more limited in marine animals than humans? A Mos
lidiya [134]

Most marine bioluminescence is blue-green, which is easier to see in the deep ocean

Explanation:

As per science,  Emission and production of light by a living organism is defined as Bioluminescence. Bioluminescence occurs widely in marine animals whereas it is triggered by a physical disturbance is seen by humans, such as a moving boat hull or waves.

Throughout the water column bioluminescent organisms live and bioluminescence is extremely common in deep sea which shows that visible spectrum is more limited to marine animals than humans.

8 0
4 years ago
What is the slope of (0,0)(4,200)
Kruka [31]

Answer:

.02

Explanation:

X-x/ Y-y= 4-0/200-0 =.02

5 0
3 years ago
Read 2 more answers
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