Explanation:
The problem says that the hairless phenotype never breeds true. That means that it's not the result of a homozygous genotype (H₁H₁ or H₂H₂), so it is caused by the heterozygous genotype (H₁H₂).
The <u>expected </u>offspring from the cross between two Mexican hairless would be:
<h3>P
H₁H₂ x
H₁H₂</h3><h3>F1 1/4
H₁H₁, 2/4
H₁H₂ and 1/4
H₂H₂.</h3>
And the <u>expected</u> phenotypic ratio 3:1. However, the observed offspring shows a 2:1 ratio. What's happening?
If the observed phenotypic ratio in the offspring of a monohybrid cross (a single gene with two alleles) is 2:1, we can suspect that one of the genotypes is lethal in homozygosis and therefore does not appear in the progeny (the puppies are born dead).
If we proposed that the H₂ allele is lethal in homozygosis, then:
- The H₁H₁ genotype would cause normal puppies --> 1
- The H₁H₂ genotype would cause hairless puppies --> 2
- The H₂H₂ is lethal and causes the death of puppies --> 0
The phenotypic ratios change to 2:1, as observed in the experiment.
Answer: No
Explanation: Since when a child is born it has DNA from both. As an example, the mom has brown hair, father has blonde hair, the child would take the DNA for the type of hair they get, either blonde or brown. So since its blood, the fathers is A, and the boy's is B, therefore it didn't take any of their DNA's so nope, he isn't the father.
European rabbits (Oryctolagus cuniculus) were introduced to Australia in the 18th century with the First Fleet and eventually became widespread. Such wild rabbit populations are a serious mammalian pest and invasive species in Australia causing millions of dollars of damage to crops.
