The correct answer is option A, that is, saturated.
The mentioned lipid is not a phospholipid, as it does not comprise a phosphate group at the terminal of the chain, and is not a triglyceride due to the absence of glycerol moiety.
Each carbon combined with the hydrogens forms the maximum number of possible C-H bonds, thus, there are no multiple bonds between the carbons. Hence, it can be concluded that the lipid is saturated.
Answer:
The Knee Flexor Muscles
Explanation: The Hamstrings All three hamstring muscles originate from the ischial tuberosity and run toward the knee. The biceps femoris muscle is inserted into the head of the fibula. It can rotate the lower leg so that the foot points laterally.
QUESTION ONE
Here are the answers:
1. The purpose of zoo described in question 1 is EDUCATIONAL: it provides knowledge about animals' lives.
2. CONSERVATION: It protects the animals from becoming extinct.
3. RESEARCH: It is a source of animal specimens for research studies.
4.ENTERTAINMENT: people go to zoos to relax and to have fun.
QUESTION 2
The statement is TRUE.
Zoo has a lot to offer in term of educating the public and that includes the topic of biodiversity. Biodiversity refers to the variety of living organisms in the world and the relationships that exist among them. Those animals have the way they relate with other organisms. Thus, the topic of biodiversity can be treated using zoo.
Answer:
on a tyrosine residue
bind to insulin
Explanation:
The insulin receptor substrate-1 (IRS1) is a signaling protein that can be phosphorylated on multiple tyrosine and serine/threonine residues. IRS1 contains several conserved domains including a pleckstrin (PH) domain and a PTB domain involved in protein phosphorylation and ligand binding. In the first place, IRS1 is phosphorylated on a tyrosine residue, and then IRS1 binds to insulin or the insulin-like growth factor-1 (IGF-1), thereby activating transduction pathways such as, for example, MAPK/ERK. Moreover, RS1 is also phosphorylated on serine residues, thereby triggering opposite effects in insulin-associated signaling.
Answer:
The answer is 83.38%.
Explanation:
The probability of young children having blood levels that impair their neurological development is given as 60% in the question. To find the probability of at least 5 children out of 10 in a sample having said blood levels, we need to use the binomial probability.
n represents the total number of children in the sample so n = 10 and p is the probability of the children having blood levels causing the problem which is 60% so p = 0.6.
We want the probability of it being observed for 5 or more children and that is 
. If we subtract the 
from 1, which is the probability of not observing the condition in 5 or more children, we will have the .
which are the probability range in the function, the sample size and the probability of observing the condition respectively.
The result is 1 - 0.1662 = 0.8338 which means that the probability that is asked is 83.38%.
I hope this answer helps.
