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Bas_tet [7]
3 years ago
4

Which is a stretch of an exponential decay function? f(x) = Four-fifths (five-fourths) Superscript x f(x) = Four-fifths (four-fi

fths) Superscript x f(x) = Five-fourths (four-fifths) Superscript x f(x) = Five-fourths (five-fourths) Superscript x
Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
6 0

Answer:

Options 2 and 3 are correct.

Step-by-step explanation:

The general form of an exponential decay function is f(x) = a(b)^{x} where b < 1.

Now, the four exponential functions are:

(i) f(x) = \frac{4}{5}(\frac{5}{4} )^{x} is not an exponential decay function as \frac{5}{4} > 1.

(ii) f(x) = \frac{4}{5}(\frac{4}{5} )^{x} is an exponential decay function as \frac{4}{5} < 1.

(iii) f(x) = \frac{5}{4}(\frac{4}{5} )^{x} is an exponential decay function as \frac{4}{5} < 1.

(iv) f(x) = \frac{5}{4}(\frac{5}{4} )^{x} is not an exponential decay function as \frac{5}{4} > 1.

So, options 2 and 3 are correct. (Answer)

andrezito [222]3 years ago
6 0

Answer:

2 and3

Step-by-step explanation:

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