What is the solution to the equation below?
2 answers:
Answer:
answer D
Step-by-step explanation:
First we simplify (using the rule
)

Then realize that this means (using the rule
):

so x = 36/4 = 9
Answer:
c
Step-by-step explanation:
yes
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Answer:115 apex
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
ax^2+bx+c=0
1/2x^2-3x-2=0
The answers to the missing angle is 40°
Answer:
![(1-sinA-cosA)^2 = 2(1-sinA)(1-cosA)\\Solution,\\L.H.S. = (1-sinA-cosA)^2 = [(1-sinA)-cosA]^2\\~~~~~~~~~~=(1-sinA)^2-2cosA(1-sinA)+cos^2A\\~~~~~~~~~~=1-2sinA+sin^2A-2cosA(1-sinA)+cos^2A\\~~~~~~~~~~=1-2sinA+sin^2A+cos^2A-2cosA(1-sinA)\\~~~~~~~~~~=1-2sinA+1-2cosA(1-sinA)\\~~~~~~~~~~=2-2sinA-2cosA(1-sinA)\\~~~~~~~~~~=2(1-sinA)-2cosA(1-sinA)\\~~~~~~~~~~=(1-sinA)(2-2cosA)= 2(1-sinA)(1-cosA)](https://tex.z-dn.net/?f=%281-sinA-cosA%29%5E2%20%3D%202%281-sinA%29%281-cosA%29%5C%5CSolution%2C%5C%5CL.H.S.%20%3D%20%281-sinA-cosA%29%5E2%20%3D%20%5B%281-sinA%29-cosA%5D%5E2%5C%5C~~~~~~~~~~%3D%281-sinA%29%5E2-2cosA%281-sinA%29%2Bcos%5E2A%5C%5C~~~~~~~~~~%3D1-2sinA%2Bsin%5E2A-2cosA%281-sinA%29%2Bcos%5E2A%5C%5C~~~~~~~~~~%3D1-2sinA%2Bsin%5E2A%2Bcos%5E2A-2cosA%281-sinA%29%5C%5C~~~~~~~~~~%3D1-2sinA%2B1-2cosA%281-sinA%29%5C%5C~~~~~~~~~~%3D2-2sinA-2cosA%281-sinA%29%5C%5C~~~~~~~~~~%3D2%281-sinA%29-2cosA%281-sinA%29%5C%5C~~~~~~~~~~%3D%281-sinA%29%282-2cosA%29%3D%202%281-sinA%29%281-cosA%29)