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BigorU [14]
3 years ago
13

I need help please ..

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0
The answer is A hope this helped
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Ponderosa Paint and Glass carries three brands of paint. A customer wants to buy another gallon of paint to match paint she purc
sveta [45]

Answer:

\frac{4}{9}

Step-by-step explanation:

Two events are independent of each other, this is called Compound Probability. Classical example is if two coins are filped, what is the probability of getting two heads in a row.?

Answer: each has 50% probability because there are two states only, either H or T. since we have two coins the probability of getting two heads in row is the product of obtaining heads for each individual coin (which is independent of each other). or is \frac{1}{2}×\frac{1}{2} = \frac{1}{4} = 25%. (Notice!).

Back to our problem, now here we have 3 paint brands and one of them is the right paint brand and two of them are not correct brands. so the prabablity that the customer has picked not correct brand is \frac{2}{3} and her husband has not picked correct brand is also \frac{2}{3}, since two probabilities are compound probabilities i.e indepandant of each other the probablity that both woman and her husband fail get correct brand is the product of the two and is = \frac{2}{3}×\frac{2}{3} = \frac{4}{9}.

4 0
2 years ago
Can you pls help me??
Ivanshal [37]

Answer:

\sqrt{10}

Step-by-step explanation:

use

a^2 +b^2=c^2

8 0
2 years ago
Read 2 more answers
100 POINTS
Svet_ta [14]

Answer:

The Great Depression

EASY

3 0
3 years ago
Guillermo compares the heights of two plants to see which plant grows more per day. The table
ivanzaharov [21]

Answer:

plant 1 grows more

Step-by-step explanation:

plant 2 only grows one cm a day while plant 2 grows 1.6 cm a day

5 0
3 years ago
Need help of simplifying each sum or difference
dimaraw [331]
First you need to get a common denominator. The first two problems already have a common denominator, so you just have to find the sum and difference of the two problems, respectively. 

6.) (9y-3)/(y^2-5)

8.) 3/xy^3

Two find a common denominator, find the smallest value that has BOTH denominators as factors. 

10.) 8x^3*y^3 is the common denominator

Answer: 2/(8*x^3*y^3)

12.) Factor x^2 + 4x + 4 to get (x+2)(x+2)

Therefore, x+2 is already part of x^2 + 4x + 4

(x+4)/(x^2+4x+4)

14.) Factor both denominators..

4(y+2) and y(y+2)

So the common denominator would be 4y(y+2)

The first fraction is missing a "y" so multiply the numerator by y to get y^2

The second fraction is missing a "4" so multiply the numerator by 4 to get 4

(y^2 - 4)/(4y(y+2))

So can factor the numerator to get (y+2)(y-2). There if a (y+2) on top and bottom so they cancel out. 

Answer: (y-2)/4y


6 0
3 years ago
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