Question

5.

Answer 1

change the mg in the question to g which is

${10}^{ - 3?}$

if 10cc contains 5g therefore

${10}^{ - 3?} \times 350 = 0.35$

0.35g would give?

$10 \times 0.35 \div 5 = 0.7cc \: of \: volume$