Answer:
f'(N) = a(k² - N²)/(k² + N²)
The function increases in the interval
(-k < N < k)
And the function decreases everywhere else; the intervals given as
(-∞ < N < -k) and (k < N < ∞)
Step-by-step explanation:
f(N)=aN/(k²+N²)
The derivative of this function is obrained using the quotient rule.
Then to determine the intervals where the function is increasinumber and decreasing,
The function increases in intervals where f'(N) > 0
and the function decreases in intervals where f'(N) < 0.
This inequality is evaluated and the solution obtained.
The solution is presented in the attached image.
Hope this Helps!!!
Hello,
ln(y)=ln(x^(ln(x))=ln(x)*ln(x)=(ln(x))²
(ln(y))'=2ln(x)*1/x
(1/y)*y'=2ln(x) / x
y'=(2 ln(x) * x^(ln(x)) ) /x
Answer: f
(
x
)
=
x
2
−
2
\x
−
3
Step-by-step explanation:
Answer:
At least <u>33</u> number of tickets can be sold in order to make a profit.
Step-by-step explanation:
Given:
A theater rents there space for $300 per night.
The company charges $9 per ticket.
Now, to find the least number of tickets that can be sold in order to make a profit.
Amount of rent per night = $300.
Charges of per ticket = $9.
So, to get the least number of tickets sold to get the profit we divide amount of rent per night by charges per ticket:
Thus, 33 tickets price is 33 × 9 = $297.
Therefore, at least 33 tickets can be sold in order to make a profit.
