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AlladinOne [14]

3 years ago

9

2 a.m. the outside temperature was 15 Fahrenheit the temperature fell steadily by 4 Fahrenheit for the next 3 hours what was the

temperature at 5 a.m.

1 answer:

KatRina [158]3 years ago

8 0

11°F is what the temperature was at 5:00 a.m.

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At a pizza shop 80% of customers order pizza

Marta_Voda [28]

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3 years ago

Which of these situations can be represented with an integer that, when combined with the opposite of 8, makes 0?

Lerok [7]

-8
On the number line if you are at positive 8 and add -8 you will lose 8 and get zero! Hope this helps!

6 0

1 year ago

There are 1,920 fences posts used in a 12- kilometer stretch of fences How many fences posts are used in 1 kilometer of fence

Nastasia [14]

1920÷12= 160

Step-by-step explanation:

1920÷12= 160

4 0

3 years ago

F represents the fee (in dollars) for climbing d meters.

Grace [21]

Answer:

$12

Step-by-step explanation:

when d = 0, F = 110

when d = 100, F = 110 + (0.12 x 100) = 122

when d = 200, F = 110 + (0.12 x 200) = 134

etc.

Therefore, increase in price for every 100 meters climbed = 134 - 122 = 122 - 110 = 12

3 0

3 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

3 years ago