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AlladinOne [14]

3 years ago

9

2 a.m. the outside temperature was 15 Fahrenheit the temperature fell steadily by 4 Fahrenheit for the next 3 hours what was the

temperature at 5 a.m.

1 answer:

KatRina [158]3 years ago

8 0

11°F is what the temperature was at 5:00 a.m.

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Write any<br>Five Places where ICT<br>tools can be used.

alexandr1967 [171]

Answer:

A Computer, The Internet, A Printer, Scanners, and Mobile Devices

Step-by-step explanation:

7 0

3 years ago

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Place the indicated product in the proper location on the grid.

marishachu [46]

Answer:

See explanation

Step-by-step explanation:

1.

$(a+b)(a^2-ab+b^2)=a^3-a^2b+ab^2+a^2b-ab^2+b^3=a^3+b^3$

2.

$(1-7x)(1+9x)=1+9x-7x-63x^2=-63x^2+2x+1$

3.

$(x+y+3)(x+y-4)=x^2+xy-4x+xy+y^2-4y+3x+3y-12=x^2+2xy+y^2-x-y-12$

4.

$(a-b)(a^2+ab+b^2)=a^3+a^2b+ab^2-a^2b-ab^2-b^3=a^3-b^3$

5.

$(m^3n+8)(m^3n-5)=(m^3n)^2-5m^3n+8m^3n-40=m^6n^2+3m^3n-40$

6.

$(4-(3c-1))(6-(3c-1))=(4-3c+1)(6-3c+1)=(5-3c)(7-3c)=35-15c-21c+9c^2=9c^2-36c+35$

7.

$(ab-9)(ab+8)=(ab)^2+8ab-9ab-72=a^2b^2-ab-72$

8.

$(a+b-c)(a+b+c)=a^2+ab+ac+ab+b^2+bc-ac-bc-c^2=a^2+b^2-c^2+2ab$

9.

$(a+3)(a-2)=a^2-2a+3a-6=a^2+a-6$

10.

$(3m^3-y)(3m^3-y)=(3m^3)^2-3m^3y-3m^3y+y^2=9m^6-6m^3y+y^2$

11.

$(2x-3y)(4x-y)=8x^2-2xy-12xy+3y^2=8x^2-14xy+3y^2$

12.

$(x^2+2x-1)(x^2+2x+5)=x^4+2x^3+5x^2+2x^3+4x^2+10x-x^2-2x-5=x^4+4x^3+8x^2+8x-5$

13.

$(4x-3y+5)(x+2y-3)=4x^2+8xy-12x-3xy-6y^2+9y+5x+10y-15=4x^2+5xy-6y^2-7x+19y-15$

8 0

3 years ago

Whats the explicit formula sequence

weeeeeb [17]

An explicit formula<span> designates the n</span>th<span> term of the </span>sequence<span>, as an expression of n (where n = the term's location). It defines the </span>sequence<span> as a </span>formula<span> in terms of n.</span>

6 0

3 years ago

Help please! I’ll give brainliest if correct!

Marrrta [24]

I think b is y would 15 and x is 3 making 15=3•5 or 15•3=45

4 0

3 years ago

: A marker in the shape of a cylinder has a diameter of 14 mm and a height of 136 mm. Find the volume of the figure described. U

Lerok [7]

Answer:

The volume of the figure is 20,925.0mm^3.

Step-by-step explanation:

Firstly we know that the Diameter = 14mm and Height = 136mm.

Area of Circle = 3.14xR^2 Radius = Diameter / 2

Area of Circle = 3.14x7mm^2 = 153.86mm

Volume = 153.86 x 136 = 20,924.96

Then round, to get 20,925.0

Let me know if this is helpful

3 0

3 years ago

Read 2 more answers