We need to solve for R, This is really simple.
The original expression is:
R (r1 + r2) = r1r2
To solve for a certain variable, we need to get this variable alone on one side of the equation and equate it with the other side.
In the given expression, to get R alone on one side we have to eliminate (r1 + r2).
In order to do this, we will divide both sides by (r1 + r2).
Doing this, we get the solution as follows:
R = (r1r2) / (r1 + r2)
To find the equation of a perpendicular line, you first need to find the negative reciprocal of the slope given. The slope is -1/3, so the slope of the perpendicular line will be 3
Now we just need to find the y intercept using the point (3, 2) and you can plug the coordinates in and then solve for b. Let's see what that looks like.
y=3x+b
2=3*(3)+b
2=9+b
-7=b So now we know the y-intercept and slope. We just put them together now
y=3x-7
Answer:
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Step-by-step explanation:
f(x) = sin (tan^-1 (ln(x)))
u substitution
d/du (sin u) * du /dx
cos (u) * du/dx
Let u =(tan^-1 (ln(x))) du/dx =d/dx (tan^-1 (ln(x)))
v substitution
Let v = ln x dv/dx = 1/x
d/dv (tan ^-1 v) dv/dx
1/( v^2+1) * dv/dx
=1/(ln^2x +1) * 1/x
Substituting this back in for du/dx
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
The negative infinity for the x coordinate states that the graph should move to the bottom and the y coordinate is positive infinity so that the graph goes up
the first graph is your answer
<h3>
Answer: 31 degrees</h3>
This is because rotations preserve angles. The angle measures won't change. That's why angle BCD is the same as angle B'C'D'. This applies to any rotation (regardless how much you rotate), any translation, any reflection, and any dilation.
Note: dilations will change the side lengths
