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3 years ago

6

The width of a rectangle is 9 in. shorter than its length.

2 answers:

Ivenika [448]3 years ago

6 0

L*W=A
L*(L-9in)=252in^2
-9in = -9in
L*L = 243in
2L=243
Do you need any more information?
Also I may be wrong but if it looks right to you than go with it. But that is what I would do.

svp [43]3 years ago

5 0

Answer:

Answer is 21 inches.

Step-by-step explanation:

I know my math.

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a 4.50 g coin of copper absorbed 54 calories of heat. what was the final temperature of the copper if the initial temperature wa

I am Lyosha [343]

The final temperature of copper is 155.43°C.

Step-by-step explanation:

The formula to apply is Q=m*Δt*c where ;

Q=heat energy, m=mass, c=specific heat capacity and Δt= change in temperature

Given that Q=54 calories , m=4.50 g and c=0.092 cal/g°C

In this question find Δt then ,the final temperature.

Δt=Q/m*c

Δt=54/4.50*0.092 =130.43°C

To find final temperature, apply the formula;

Δt=Final temperature - Initial temperature

130.43°C=Final temperature-25°C

130.43°C+25°C=Final temperature

155.43°C

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Specific Heat Capacity : brainly.com/question/12431744

Keyword : specific heat capacity

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4 years ago

Generate the nest three terms of each arithmetic sequence shown below.

o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{2}=a_{1}+(2-1)d$

$a_{2}=a_{1}+(1)d$

Substituting the given value we get

$a_{2}= -2+(1)4$

$a_{2}= -2+4$

$a_{2}= 2$

------------------------------------------

Similarly

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the given value we get

$a_{3}= -2+(2)4$

$a_{3}= -2+8$

$a_{3}= 6$

-------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the given value we get

$a_{4}= -2+(3)4$

$a_{4}= -2+16$

$a_{4}= 10$

-------------------------------------------------------------------------------------------

<u>B</u><u> $a_n=a_{(n-1)}-8$ with $a_1=10$ </u>

$a_2=a_{(2-1)}-8$

$a_2=a_{1}-8$

Substituting the given value

$a_2= 10-8$

$a_2=2$

---------------------------------------------------------------------

$a_3=a_{(3-1)}-8$

$a_3=a_{2}-8$

Substituting the value

$a_3=2-8$

$a_3= -6$

---------------------------------------------------------------------

$a_4=a_{(4-1)}-8$

$a_4=a_{3}-8$

Substituting the value

$a_4= -6-8$

$a_4= -14$

-------------------------------------------------------------------------------------------

<u>C) $a_1=3, a_2=1$ </u>

Here the difference is -2

the arithmetic sequence formula is

$a_{n}=a_{1}+(n-1)d$

Now

$a_{3}=a_{1}+(3-1)d$

$a_{3}=a_{1}+(2)d$

Substituting the value we get

$a_{3}= 3+(2)-2$

$a_{3}= 3-4$

$a_{3}= -1$

------------------------------------------------------------------------------

$a_{4}=a_{1}+(4-1)d$

$a_{4}=a_{1}+(3)d$

Substituting the value we get

$a_{4}= 3+(3)-2$

$a_{4}= 3-6$

$a_{4}= -3$

----------------------------------------------------------------------------------

$a_{5}=a_{1}+(5-1)d$

$a_{5}=a_{1}+(4)d$

Substituting the value we get

$a_{5}= 3+(4)-2$

$a_{5}= 3-8$

$a_{5}= -5$

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3 years ago

a teacher awarded 50 marks to his least student in a class test. How many marks was awarded to the best student if he was 40% be

LenaWriter [7]

Answer:

90 marks per that student

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(2h – 3)(3h + 4) is the same thing as

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6h^2 - h - 12

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3 years ago

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3 years ago