HE NEEED SOME MILK
HE NEED SOME MILK
Answer:
B. take classes in high school that will give her college credit.
Explanation:
This is one of the ways in which Sheila might be able to attend college. By taking some classes in high school that will give her college credit, Sheila would most likely lessen the load of classes that she has to take in college. This will allow her to take less classes in college each year, reducing the fees she pays. Otherwise, she could also choose to take more classes each year, but stay in school for less time. Either way, her tuition costs are likely to be lower.
1) ii x ii, the square would have an i next to every box and ii in every space. Ratio is 100% ii.
2) AA x BB. Across the top both are As and on the side both Bs. All boxes are filled with AB. Ratio is 100% AB.
3) Ai x Bi. Across the top there is a large A and an i. Across the side is a B and an i. At the spot both A and B meet, you have AB, where A and i meet you have Ai, B and i meet at Bi, and i and i meet for ii. Ratio is 25% AB, 25% Bi, 25% Ai, 25% ii.
4) ii x AB. Across the side is i on both, and on top is A and B. Both under A in the boxes would be Ai and both under B would be Bi. Ratio is 50% Ai, 50% Bi.
5) AB x AB. Across the top is A then B and down the side is A and B. Where the As meet is AA, where the Bs meet is BB, and where A and B meet is AB. Ratio is 50% AB, 25% AA, 25% BB.
6) Alice has Ai and Mark has Bi. On the square, across the top first is an A and second is an i, and down first is B second i. In the boxes where A and B combine is AB, where A and i combine is Ai, B and i is BI, and i and i is ii.
7) No, it is not possible, there is no way to give an i phenome. In the square across the top draw A and B on separate rows, and for the ones under A draw a big A and the ones under B a big B.
8) the baby can have type O blood. Ralph’s phenotype is Bi and Rachel is Ai. Across the top put B then i, and on the side A then i. At the intersection of A and B put AB, the intersection between A and i put Ai, between B and i put Bi, and from i and i put ii.
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