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Kipish [7]
3 years ago
12

Write a number with one decimal place, that is bigger than 3 but smaller than 4

Mathematics
2 answers:
Greeley [361]3 years ago
7 0
The answer is 3.5 because it’s smaller than 4 but bigger than 3
Artist 52 [7]3 years ago
7 0

Answer:

The answer can be 3.1, 3.2, 3.3, 3.4, 3.5, 3.6, 3.7, 3.8, or 3.9.

Step-by-step explanation:

All of those work

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Determine whether the stated conclusion is valid based on the given information. Explain your reasoning.
Oduvanchick [21]
The answer is D. The law of detachment states that
"If P than Q. P."
In this case passing the bar exam is P and getting to practice law is Q. So if we know that Candice is allowed to practice law if she passes the bar exam and that she did pass the exam. The conclusion that Candice can now practice law is valid.
4 0
3 years ago
What is the area of the hexagon?
Gnoma [55]

Answer:

Around 60.32 squared

Step-by-step explanation:

Area = (3√3 s2)/ 2 where s is the length of a side of the regular hexagon.

6 0
3 years ago
Read 2 more answers
You don't have to draw a line you can just type the volumes in terms of PI and just normal.
Nikolay [14]
Dill pickle 10.6^ units
3 0
3 years ago
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Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
Question 8 (06.02 LC)
kodGreya [7K]
Question 8.
The best answer would be A, two times y divided by 7.

Question 9.
The distributive property. Or A.

Question 10.
5(2+y) would be the answer. So, D.

Hope this helps!


8 0
3 years ago
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