5+(x-5)=x
Simplify the left side by combining like terms:
5 + x - 5 = x
5-5 = 0
x = x
X = All real numbers.
there is no B i see A and -5A unless its for -5A??
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
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Step-by-step explanation:
