Since they’re both in standard form and they both say that y is equal to something, you just have to set them up with one another
2x-10=4x-8
Subtract 2x
-10=2x-8
Add 8
-2=2x
Divide by 2
-1=x
x=-1
Check it by inserting it
2(-1)-10=4(-1)-8
-2-10=-4-8
-12=-12
So x=-1 is the answer
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Calculator lolololol nah joking first
That question is accompanied by these answer choices:
<span>A. The scale is accurate but not precise.
B. The scale is precise but not accurate.
C. The scale is neither precise nor accurate.
D. The scale is both accurate and precise.
Then you need to distinguish between accuracy and precision.
Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report.
The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.
So, the answer is that the scale is precise but not accurate (the option B</span>
(a) The differential equation is separable, so we separate the variables and integrate:
When x = 0, we have y = 2, so we solve for the constant C :
Then the particular solution to the DE is
We can go on to solve explicitly for y in terms of x :
(b) The curves y = x² and y = 2x - x² intersect for
and the bounded region is the set
The area of this region is
