Answer:
I think x = 1 but I’m not sure I’m sorry
Step-by-step explanation:
Answer: No solutions exist because the situation describes two lines that have the same slope and different y-intercepts.
Answer:
x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
Step-by-step explanation:
Solve for x:
2 x^2 - 5 x + 5 = 0
Hint: | Using the quadratic formula, solve for x.
x = (5 ± sqrt((-5)^2 - 4×2×5))/(2×2) = (5 ± sqrt(25 - 40))/4 = (5 ± sqrt(-15))/4:
x = (5 + sqrt(-15))/4 or x = (5 - sqrt(-15))/4
Hint: | Express sqrt(-15) in terms of i.
sqrt(-15) = sqrt(-1) sqrt(15) = i sqrt(15):
Answer: x = (5 + i sqrt(15))/4 or x = (5 - i sqrt(15))/4
The pebble slowly falls and it's in the middle of the surface and bottom
Complete the square fr x and y's sepreatly to get into form
(x-h)²+(y-k)²=r²
the center is (h,k) and radius is r
so
group x's and y's seperatly
(4x²-10x)+(4y²+24y)+133/4=0
undistribute leading confident from each
4(x²-2.5x)+4(y²+6y)+133/4=0
take 1/2 of each linear confident and square it and add negative and positive inside the parenthasees
-2.5/2=-1.25 (-1.25)²=1.5625
6/2=3, 3²=9
4(x²-2.5x+1.5625-1.5625)+4(y²+6y+9-9)+133/4=0
factor perfect squares
4((x-1.25)²-1.5625)+4((y+3)²-9)+133/4=0
expand
4(x-1.25)²-6.25+4(y+3)²-36+133/4=0
4(x-1.25)²+4(y+3)²-9=0
add 9 to both sides
4(x-1.25)²+4(y+3)²=9
divide both sides by 4
(x-1.25)²+(y+3)²=9/4
(x-1.25)²+(y+3)²=(3/2)²
the center is (1.25,-3) and the radius is 1.5
