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AlekseyPX
4 years ago
7

Perform the following division 3 3/4÷2/8

Mathematics
1 answer:
tamaranim1 [39]4 years ago
8 0
<span>3 3/4 ÷ 2/8
=15/4 </span>÷ <span>2/8
</span>=15/4 <span>×</span> 8/2
=120/8
=15
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please help John's age increased by 11 is 5 less than 5 times his age. How old is he? If x represents John's age, which of the f
Keith_Richards [23]
So x is John's age.
We can solve this problem by working backwards.
Since it's 5 times his age, we first do 5x.
And then since it's five less, we move on to 5x - 5
And then we add the John's age is increased by 11: 5x - 5 = x + 11
I hope this helped :)
(It should be the second one you listed)
7 0
3 years ago
Square root of 8 + 12 is it rational o rational
IRISSAK [1]

Answer:

rational

Step-by-step explanation:

both 8 and 12 are rational and we are adding rationals number

5 0
3 years ago
Which of the following would be an appropriate horizontal and vertical scale of a viewing window on a graphing calculator for th
Tpy6a [65]
The eee part is the right part because I’m not trying to get points I’m so sorry
4 0
3 years ago
List all number sets that apply to each number
kolbaska11 [484]

Answer:

45

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224

Step-by-step explanation:

5 0
3 years ago
Given an equilateral triangle that has an area of 1959 cm2. What is the length of its sides?
Nina [5.8K]
Equilateral
equi means equal
lateral means sides

all sides are equal
triangle has 3 sides

perimiter=side1+side2+side3
side1=side2=side3


area=1/2 times base times height
base=side
draw a line down the middle of te tiangle so you get 2 right triangles side by side
1/2base is one leg
base is hypotonuse
height is unknown
equilateral means that it is a 30-60-90 triangle with  hypotonuse equal to 2x, height=x√3, bottom is x
1/2 times base times height=1959
1/2 times x times x√3=1959
multiply both sides by 2
(x^2)√3=3918
divide both sides by √3
x^2=3918/√3
square root both sides
x=47.5611
side=hypotonuse=2x
2x=2*47.5611
side=95.12222


legnth of each side is 2\sqrt{ \frac{3918}{ \sqrt{3} } }cm or about 95.12222 cm
7 0
3 years ago
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