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IceJOKER [234]
3 years ago
15

If line A contains the points (3, -4) and (6, -2), and line B contains the points (-1, 5) and (1, 2), prove that the lines are p

erpendicular by multiplying their slopes.
Mathematics
1 answer:
vivado [14]3 years ago
7 0

Answer:

Correct answer:  sa · sb = 2/3 · (- 3/2) = - 1

Step-by-step explanation:

Given:

line A - (x₁, y₁) = (3, -4)   and (x₂, y₂) = (6, -2)

line B - (x₁, y₁) = (-1, 5)   and (x₂, y₂) = (1, 2)

The slope is calculated using the following formula:

s = (y₂ - y₁) / (x₂ - x₁)

sa = (-2 - (-4)) / (6 - 3) = (-2 + 4) / 3 = 2 / 3

sa = 2 / 3

sb = (2 - 5) / (1 - (-1)) = -3 / 2

when lines are perpendicular to each other then the slopes are in the next relationship:

sa · sb = - 1

we will check:

sa · sb = 2/3 · (- 3/2) = - 1

God is with you!!!

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velikii [3]
A - 1.2b = - 3         ⇒ eq. 1
0.2b + 0.6a = 12   ⇒ eq. 2

a - 1.2b = - 3  
a = 1.2b - 3           ⇒ eq. 3

Substitute eq. 3 to eq. 2
0.2b + 0.6(1.2b - 3) = 12
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Combine like terms
0.92b = 12 + 1.8
0.92b = 13.8   ⇒ divide both sides by 0.92 to get the value of b
<span>b = 15

</span>Substitute the value of b to eq. 3
a = 1.2b - 3
a = 1.2(15) - 3 
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</span>to check: substitute the values of a and b to:
eq. 1
a - 1.2b = - 3 
15 - (1.2)(15) = -3 
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eq. 2 
0.2b + 0.6a = 12 
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3 + 9 = 12
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