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Lerok [7]
3 years ago
9

Jose wants to fence in his garden. The shape is a rectangle. Two sides are each 12 feet long. The other two sides are each 108 i

nches long. He buys 40 feet of fence.
Part A

What are steps he must take to see if he bought enough fence? Select all that apply.

A.
Convert both side lengths to the same unit.

B.
Find the area of the garden.

C.
Add 12 feet and 108 inches to find the perimeter of the garden.

D.
Compare the number of feet of fence he bought with the number of feet of fence he needs.

Part B

Did he buy enough fence?

A.
no

B.
yes
Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0
The answer is To your question is C
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2

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Lisa an experienced shipping​ clerk, can fill a certain order in 7 hours. ​bill, a new​ clerk, needs
OLga [1]

Answer:

3.73 hours

Explanation:

In 1 hour, Lisa does 1/7th of the order while Bill does 1/8th of the order in an hour. To find out how long it will take them to fill the order, we have to:

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Add the rate of both Lisa and Bill together

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Step 2:

Since both denominators of the fractions are different, you have to find the least common multiple of 7 and 8

7·8= 56    8·7= 56

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The fractions would now have equal denominators:

Lisa: 8/56    Bill: 7/56

Step 4:

Now, you can add them together

8/56 + 7/56

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Step 5:

15/56 is not the final answer as it is the RATE of them working together. To find how long it will take them total to complete the order, you must divide 56 with 15.

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3 years ago
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7 0
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Read 2 more answers
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
EastWind [94]

Answer:

(52-49) -4.300= -1.300

(52-49) +4.300= 7.300

And the 95% confidence would be :

-1.300 \leq \mu_1 -\mu_2 \leq 7.300

Step-by-step explanation:

We have the following info given from the problem

\bar X_1 = 52 sample mean for this year

s_1= 13 sample deviation for this year

n_1 = 75 random sample selected for this year

\bar X_2 = 49 sample mean for last year

s_2= 11 sample deviation for last year

n_1 = 53 random sample selected for last year

And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales

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(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

The degrees of freedom are given by:

df= n_1 +n_2 -2 = 75+53-2= 126

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t_{\alpha/2}= 1.979

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ME = 1.979 \sqrt{\frac{13^2}{75} +\frac{11^2}{49}}= 4.300

And the confidence interval would be given by:

(52-49) -4.300= -1.300

(52-49) +4.300= 7.300

And the 95% confidence would be :

-1.300 \leq \mu_1 -\mu_2 \leq 7.300

6 0
4 years ago
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