Virtual memory frees up RAM by transferring data that hasn't recently been used to a storage device, such as a hard disk or solid-state drive (SSD). Virtual memory is useful for multitasking, running large programs, and speeding up the system.
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What is the role of virtual memory in disk storage space?</h3>
Virtual memory fulfills two functions. First, by using disk, it enables us to increase the utilization of physical memory. Because each virtual address is converted to a physical address, it also enables memory protection.
An operating system may load programs larger than its physical memory thanks to virtual memory, which is its fundamental benefit. The users get the idea that the machine has boundless memory. Additionally, it offers memory security.
Therefore, operating systems move code and data, as necessary, to a portion of the disk that is used as if it were memory, not just disk storage space.
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The answer is definitely (A. SQL server) it was released back in 2010 and is huge!
Let us know if there is anything else you need to know.
Mark brainlest :)
Answer:
1066.67 N
Explanation:
Given that two measurements of the arm and an input weight. To answer this problem,we need to balance the forces and use the lengths of the arms.
Force × effort of arm distance= input weight × load distance
200 N * 8 m = x * 1.5 m
1600 = 1.5x
x = 1600/1.5
x = 1066.666 N
it takes 1066.67 N to lift the input weight
Answer: The difference between call by value and call by reference is that in call by value the actual parameters are passed into the function as arguments whereas in call by reference the address of the variables are sent as parameters.
Explanation:
Some examples are:
call by value
#include <stdio.h>
void swap(int, int);
int main()
{ int a = 10, b= 20;
swap(a, b);
printf("a: %d, b: %d\n", a, b);
}
void swap(int c, int d)
{
int t;
t = c; c = d; d = t;
}
OUTPUT
a: 10, b: 20
The value of a and b remain unchanged as the values are local
//call by reference
#include <stdio.h>
void swap(int*, int*);
int main()
{
int a = 10, b = 20;
swap(&a, &b); //passing the address
printf("a: %d, b: %d\n", a, b);
}
void swap(int *c, int *d)
{
int t;
t = *c; *c = *d; *d = t;
}
OUTPUT
a: 20, b: 10
due to dereferencing by the pointer the value can be changed which is call by reference
Answer:
Let the function be Node* ins(Node *root,int k)
if root node is NULL then return new node with data equal to k.
If the k <root->data
root->left=ins(root->left,k);
else if k >root->data
root->right =ins(root->right,k);
At last return root.
Explanation:
Node is always inserted at the at the leaf node.We will search k in the tree if we hit a the leaf node the new node is inserted as the child of the leaf node.
