Answer:
w+4 is bigger!
Step-by-step explanation:
0 is worth nothing

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if
</span><span>

</span><span>In notation we write respectively
</span>

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence

Thus these two limits, the one from above and below are equal if and only if
4c + 20 = 16 - c²<span>
Or in other words, the limit as x --> 4 of f(x) exists if and only if
4c + 20 = 16 - c</span>²

That is to say, if c = -2, f(x) is continuous at x = 4.
Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers 
Answer:
270 feet
Step-by-step explanation:
For clarity, the image below represents the problem. Let's call h the height of the tower. Notice that it forms 2 triangles that are similar to side-angle-side. So, we can calculate the higher of the tower by similar triangles:
higher1/base1 = higher2/base2
h/135 = 6/3
h/135 = 2
h = 270 ft
Answer:
the solutions are c because, when we say x +7=81 that will give us 74 which is there on c