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pochemuha
3 years ago
15

How many solutions does each equation have

Mathematics
2 answers:
notka56 [123]3 years ago
7 0

Answer:

sex kaise kare aur bata ky chal raha tha aur bata ky chal raha h

Gnom [1K]3 years ago
6 0
Yes it does you see
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Either enter an exact answer in terms of T or use 3.14 for 7 and enter your answer as a decimal.
muminat

Answer:

N CCX  XN

Step-by-step explanation:

7 0
2 years ago
(2+5xyz-6tv²c)-(11-5yxz-2ctv²)​
Effectus [21]

Answer:

-4ctv² + 10xyz - 9

Step-by-step explanation:

(2 + 5xyz - 6tv²c) - (11 - 5yxz - 2ctv²)

2 + 5xyz - 6tv²c - 11 + 5yxz + 2ctv²

-4ctv² + 10xyz - 9

I hope this helps!

5 0
2 years ago
Which pairs of angels in the figure below are vertical angles?​
Arada [10]
B has the pair that are vertical angles
8 0
3 years ago
Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
Solve the inequality.<br> 15 The solution of the inequality is___<br> Pls help!!!!!!!!!
nlexa [21]

Answer:

hsgsjskvshsjsvdjsmz

Step-by-step explanation:

hshshjsdbhwjsbdiaksbudjs

5 0
3 years ago
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