3 years ago

A car costs £9000. Its value depreciates at 15% per year. Find the value of the car after 1 year.

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

5 0

It depreciates at 15%, which means it would be valued at 85% of the previous value.

After one year the value would be 9000 x 0.85 = £ 7650

You might be interested in

45 1/2% percent as a fraction in simplest form

topjm [15]

45.5%, or 4.55, for 455/1000.

91/200

8 0

3 years ago

Read 2 more answers

Solve 0.9 x + 5.1 x -7= 2(2.5x-3). how many solutions dose the equation have?

Nataly [62]

The equasion has only one solution.

4 0

3 years ago

Let f(x) ln(1+t^2)dt find f'(x) find the critical numbers of f g

OverLord2011 [107]

X1y hope it helps I'm just starting out

7 0

3 years ago

The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil

satela [25.4K]

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

$z = \frac{y}{2}$ ------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

$y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16$

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

5 0

3 years ago

Can you please help me?

larisa [96]

Replace the words with what you know
(Original cost)(6%)=5.25
(Original cost)(0.06)=5.25
(original cost)=5.25/0.06=87.5

6 0

3 years ago

Read 2 more answers