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musickatia [10]
3 years ago
11

Valor absoluto de -10 =

Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0
10
7
39
52
325
125
33
1232
11525
20205

Bien!
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Any polygon can be the base of a prism. A. True B. False​
Viefleur [7K]

Answer:

I'm pretty sure it's true sorry if it's wrong!

5 0
3 years ago
Solve the following system of equations<br><br> 3x - 2y =5<br><br> -2x - 3y = 14
stepladder [879]

Answer:

x = -1 and y = -4

Step-by-step explanation:

It is given that,

3x - 2y = 5     ----(1)

-2x - 3y = 14 ------(2)

<u>To find the solution of equations</u>

(1) * 2 ⇒

6x - 4y = 10  -----(3)

(2) * 3 ⇒

-6x - 9y =  42   ----(4)

eq(3) + eq(4) ⇒

6x - 4y = 10  -----(3)

<u>-6x - 9y =  42 </u>  ----(4)

 0   - 13y = 52

y = 52/(-13) = -4

Substitute the value of y in eq(1)

3x - 2y = 5     ----(1)

3x - (2 * -4) = 5

3x  +8 = 5

3x = 5 - 8 = -3

x = -3/3 = -1

Therefore x = -1 and y = -4

5 0
3 years ago
Read 2 more answers
4cos^2(theta)+2sin(theta)=2
DedPeter [7]

Answer:

The value of given expression i.e Ф is 90°  and - 30°

Step-by-step explanation:

Given as :

4 cos²Ф + 2 sinФ = 2

∵  sin²Ф +  cos²Ф = 1  ,  so ,  cos²Ф = 1 -  sin²Ф

Or, 4 ( 1 - sin²Ф ) + 2 sinФ = 2

Or, 4 - 4 sin²Ф + 2 sinФ = 2

or, 4 sin²Ф - 2 sinФ - 4 + 2 = 0

or, 4 sin²Ф - 2 sinФ - 2 = 0

or, 2 sin²Ф -  sinФ - 1 = 0

or, 2 sin²Ф - 2 sinФ +  sinФ - 1 = 0

Or, 2 sinФ ( sinФ - 1 ) + 1 ( sinФ - 1 ) = 0

∴  ( sinФ - 1 ) ( 2 sinФ + 1 ) = 0

i.e  ( sinФ - 1 ) = 0  And  ( 2 sinФ + 1 ) = 0

since   ( sinФ - 1 ) = 0  

So, sinФ  = 1

Or,  Ф = sin^{-1}(1) = 90°

And ( 2 sinФ + 1 ) = 0

Or,  2 sinФ = - 1

Or,  sinФ = - \frac{1}{2}

Or,   Ф = sin^{-1}(-\frac{1}{2}) = - 30°

Hence the value of given expression i.e Ф is 90°  and - 30°    Answer

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3 years ago
Complete the T and graph the equation y = x+2
jonny [76]
Slope 1
y intercept 2
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