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Gennadij [26K]
2 years ago
12

Anyone? i dont understand

Mathematics
1 answer:
Murljashka [212]2 years ago
8 0

Answer:

1725ft^2

Step-by-step explanation:

Hi!

First you have to find your two bases B1 and B2, which are 50 and 65.

Then you find the height, which is 30ft.

Finally, you plug those into the equation 1/2*h*(B1+B2) and solve.

1/2*30*(50+65)

1/2*30*(115)

15*115

1725ft^2 is your answer.

I hope this helps!

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Check the picture below.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}

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\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0
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