The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
Calculating (5 x 2) violates the order of operations
Step-by-step explanation:
According to the order of operations, multiplies all have equal priority. Therefore, they must be evaluated left to right, not right to left. Evaluating (5 x 2) first is incorrect, and instead (9 x 5) should be calculated first.
27+ 2/5×-1/2 = 27 - 1/5
(135 - 1)/5 = 134 /5 <——answer
2nd one is the correct one I think
