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Rom4ik [11]
3 years ago
8

a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the

function h(t) = -16t^2+25t+3 after how many seconds will the balloons hit the ground?
Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}
x=\frac{-25+/-\frac{625+192}}{-32}
x=\frac{-25+/-\frac{817}}{-32}
it has to be a positive time

so it will hit the ground after \frac{25+\sqrt{817}}{32} seconds
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