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2 years ago

15

a professional baseball pitcher was capable of throwing a baseball 160 ft/s. during his career, he had the opportunity to pitch

in the Houston astrodome,

1 answer:

Eduardwww [97]2 years ago

6 0

Answer:

wheres the rest of question?

Step-by-step explanation:

You might be interested in

The sum of five consecutive integers is 55. Find the integers.

liubo4ka [24]

Answer:

9, 10, 11, 12, 13

Step-by-step explanation:

(x-2)+(x-1)+x+(x+1)+(x+2) = 55

5x = 55

x = 11

8 0

2 years ago

Check Which pair of angles is complementary?

sergey [27]

The third set of angles is complementary. Complementary angles are angles that add up to 90°.

56° + 34° = 90°

6 0

3 years ago

Read 2 more answers

What is the GFC of 40 and 60

Svetradugi [14.3K]

Answer:

GCF: 20

Step-by-step explanation:

The thing you want to do is factor both numbers down to their lowest primes.

40:2 * 2 * 2 * 5

60:2 * 2 * 5 * 3

Now underline what is in both sets of primes. I'll bold them. The number that is bolded comes from 2 * 2 * 5 which is 20

The highest common factor is 20

3 0

3 years ago

if Val planted 36 pumpkin seeds in the community garden. In two weeks, (11) 27 of the seeds had germinated. What percent of the

garik1379 [7]

Answer: I'm not completly certain but, try 27% and see if it's right.

Step-by-step explanation:

4 0

2 years ago

Determine whether the equation defines y as a function of x.<br> x+y=9 and x^2+y^2=1 and x=y^2

Murrr4er [49]

Answer:

Function: $x+y=9$

Not Function: $x^2+y^2=1$ and $x=y^2$

Step-by-step explanation:

Given

$x+y=9$

$x^2+y^2=1$

$x=y^2$

Required

Determine if $y$ is a function of $x$

Solving x+y=9

$x+y=9$

Make y the subject of formula

$y = 9 - x$

<em>Hence; y is a function of x</em>

Solving $x^2+y^2=1$

$x^2+y^2=1$

Subtract x² from both sides

$y^2=1 - x^2$

Square root of both sides

$y =\± \sqrt{1 - x^2}$

This implies that

$y =\sqrt{1 - x^2}$ or $y =-\sqrt{1 - x^2}$

<em>Because </em> $y$ <em> can be any of those two expressions, it is not a function.</em>

Solving $x=y^2$

$x=y^2$

Reorder

$y^2 = x$

Take square roots

$y = \±\sqrt{x}$

This implies that

$y = \sqrt{x}$ or $y = -\sqrt{x}$

<em>Because </em> $y$ <em> can be any of those two expressions, it is not a function.</em>

4 0

3 years ago