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Paraphin [41]
3 years ago
5

List these least to greather 5,-2,-1,4

Mathematics
1 answer:
zhenek [66]3 years ago
8 0
This will be from least to greater -1 -2 4 5
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-5x-12>6x-4 Solve the inequality and give the answer in interval notation.
lora16 [44]

-5x-12>6x-4

To Solve the inequality we need to get x alone

-5x-12>6x-4

first we remove -12, for that we add 12 on both sides

-5x-12+12>6x-4+12

-5x > 6x +8

Now subtract 6x from both sides

-5x -6x> 6x-6x +8

-11x > 8

Divide by -11. when we divide by -11 we flip the inequality . so > becomes <

x < -\frac{8}{11}

We need to give the answer in interval notation.

x is less than -8/11 so x value starts from -8/1  and goes to -infinity(left)

So interval notation is (-∞, -\frac{8}{11})

7 0
3 years ago
Solve the system of equations: <br> X+y+z=5<br> -3x-4y+4z=15<br> 2x-y-4z=-8
kolezko [41]

Answer:

Solution By Gauss jordan elimination method

x = 3, y = 2 and z = 4

6 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
Write the equation of the line represented on the graph.
Marianna [84]

Answer:

y=-\frac{3}{2} x+3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help with this question!
Nostrana [21]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

a ) Two matrices cannot be multiplied.

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

b )

The answer is | 20 - 4 - 12 |

| 8 2 19 - |

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

7 0
3 years ago
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