Answer:
20![\pi](https://tex.z-dn.net/?f=%5Cpi)
Step-by-step explanation:
Circumference formula: ![2\pi r](https://tex.z-dn.net/?f=2%5Cpi%20r)
Since the diameter is 20, the radius will be half of the diameter
r=d/2, where d=20
r=20/2=10
C=![2\pi r](https://tex.z-dn.net/?f=2%5Cpi%20r)
C=2(10)![\pi](https://tex.z-dn.net/?f=%5Cpi)
C=20![\pi](https://tex.z-dn.net/?f=%5Cpi)
<h3>
<u>Explanation</u></h3>
- Given 5,6 and 7 part of the y-term.
![\begin{cases}5 \in y \\ 6 \in y \\ 7 \in y \end{cases}](https://tex.z-dn.net/?f=%20%5Cbegin%7Bcases%7D5%20%5Cin%20y%20%5C%5C%206%20%5Cin%20y%20%5C%5C%207%20%5Cin%20y%20%5Cend%7Bcases%7D)
![y + 4 < 10 \\ y < 10 - 4 \\ y < 6](https://tex.z-dn.net/?f=y%20%2B%204%20%3C%2010%20%5C%5C%20y%20%3C%2010%20-%204%20%5C%5C%20y%20%3C%206)
Therefore, the value of y is lesser than 6. That meane it can't be y = 6 or greater. Hence, 5 is the solution to the Inequality.
<h3>
<u>Answer</u></h3>
y = 5 is the solution to the Inequality.
But if you want to solve for Inequality only then it is y < 6
If q<span>uadrilateral AGHYis congruent to quadrilateral BFRS, then
</span>
![\angle A\sim \angle B](https://tex.z-dn.net/?f=%5Cangle%20A%5Csim%20%5Cangle%20B)
,
![\angle G\sim \angle F](https://tex.z-dn.net/?f=%5Cangle%20G%5Csim%20%5Cangle%20F)
,
![\angle H\sim \angle R](https://tex.z-dn.net/?f=%5Cangle%20H%5Csim%20%5Cangle%20R)
,
![\angle Y\sim \angle SB](https://tex.z-dn.net/?f=%5Cangle%20Y%5Csim%20%5Cangle%20SB)
and
![AG\sim BF](https://tex.z-dn.net/?f=AG%5Csim%20BF)
,
![GH\sim FR](https://tex.z-dn.net/?f=GH%5Csim%20FR)
,
![HY\sim RS](https://tex.z-dn.net/?f=HY%5Csim%20RS)
,
![AY\sim BSF](https://tex.z-dn.net/?f=AY%5Csim%20BSF)
.
251/50 or mixed number is 5 1/50