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djverab [1.8K]
3 years ago
10

Please help please help

Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0
Pretty sure it is B?
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A textile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 ki
shepuryov [24]

Answer

given,

mean = 12 Kg

standard deviation = 0.5 Kg

assume the observed statistic is = 11.1

 now, \bar{X}=11.1 , \mu = 12 , \sigma = 0.5

assuming the number of sample = 4

n = 4

Hypothesis test:

H₀ : μ≥ 12

Ha : μ < 12

now,

significant level α = 0.05

z* = \dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z* = \dfrac{11.1-12}{\dfrac{0.5}{\sqrt{4}}}

     z* = -3.60

Test statistics, Z* = -3.60

P-value

P(Z<-3.60) = 0.002 (from z- table)

P- value = 0.002

now,

reject the value of H₀ when P-value < α

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since, it is less P-value < α , we have to reject the null hypothesis

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3 years ago
Least to greatest 63.37,62.95,63.7
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Answer:

1.  62.95

2.  63.37

3.  63.7

Step-by-step explanation:

List the numbers by lining up the decimals and filling in zeros in the empty spaces to make all the numbers have the same number of digits,  then compare whole numbers first then the decimals.  There are two 63's so then you look at the decimal side one is .37 and one is .70 (add the zero so all numbers have the same number of digits)

63.37

62.95

63.70 (added the zero)

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I think the answer is B
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Please mark me the brainiest!
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