The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
The answer is 888+88+8+8+8
Answer:
option B and C
Step-by-step explanation:
option B and C
Answer:
Step-by-step explanation:
Since there's no one one number you can add to one number in the sequence to get to the next number, this is not arithmetic. It must be geometric. We need then to find the common ratio. Let's start with the first 2 numbers, find a ratio, and then use it to test for accuracy.
10x = 15 and
x =
If this is in fact a geometric sequence witha common ratio of 3/2, we should be able to multiply 15 by 3/2 to get to the next number in the sequence. Let's try it out:
Good. So the common ratio is 3/2. The formula for an explicit geometric formula is
where a1 is the first number in the sequence and r is the common ratio. Filling in:

Answer:
x^9/8
Step-by-step explanation:
The exponent property that you can use here is that when multiplying the two exponents, you add their exponents
Thus, (x^7/8) (x^1/4) = x^(7/8+1/4)=x^9/8