Answer:
domain: 2x+1 not equal to zero, then x not equal to -1/2
Set 2x+1>0
then x>-1/2
100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)
100^(3-4x)<=0.01^(5x-8)
(10^2)^(3-4x)<=[10^(-2)]^(5x-8)
10^[2*(3-4x)]<=10^[(-2)*(5x-8)]
10^(6-8x)<=10^(16-10x)
6-8x<=16-10x
2x<=10
x<=5
combine x>-1/2 and x<=5
then - 1/2<x<=5
Set 2x+1<0
then x<-1/2
100^(3-4x)/(2x+1)<=0.01^(5x-8)/(2x+1)
100^(3-4x)>=0.01^(5x-8)
(10^2)^(3-4x)>=[10^(-2)]^(5x-8)
10^[2*(3-4x)]>=10^[(-2)*(5x-8)]
10^(6-8x)>=10^(16-10x)
6-8x>=16-10x
2x>=10
x>=5
combine x<-1/2 and x>=5
, then x does not exist while 2x+1<0
so answer is - 1/2<x<=5
Answer:
36/45 and 35/45
Step-by-step explanation:
5 and 9's least common denominator is 45 and to get to that you need to multiply both top and bottom of how to get to 45. How I got to 45 the easiest way is to keep multiplying both numbers until the reach the same product. In this case for 4/5, you multiply it by 9 for top and bottom. And for 7/9, it would be multiplying by 5 for top and bottom which will get you both of the answers. Hopefully this answers your question.
Answer:
3x^2 + 10x
Step-by-step explanation:
If u wrote it correctly it would be ((x+4+2)+4)(x)
Answer:
I'm only in 7th grade
Step-by-step explanation: