Answer:
$6.03
Step-by-step explanation:
Let's begin by listing out the given variables:
height (h) = 12 cm, diameter (d) = 8 cm, r = d ÷ 2 ⇒ r = 4 cm, cost of coconut oil (c) = $0.01 /cm³
The formula of cylinder is given by:
V = πr²h = π * 4² * 12 = <u>603.1858 cm³</u>
cost of filling the tin can with coconut oil = cost of coconut oil * Volume of cylinder
Cost = c * V = 0.01 * 603.1858
Cost = $<u>6.03</u>
The last one is the answer
Answer:
<h2>32/1125</h2>
Step-by-step explanation:
Probability is the likelihood or chance that an event will occur.
Probability = Expected outcome of event/Total outcome.
If a video rental store keeps a list of their top 15 movie rentals each week, the total outcome is 15.
If the list for the week includes 6 action, 4 comedies, 3 dramas, and 2 mysteries and the store manager removes a copy of each of the 15 movies from the shelf, then randomly selects 3 of the 15 to show on the display monitors in the store, the probability that she selected 2 comedies and 1 action movie will be calculated as shown;
Probability of selecting 2 comedies = 4/15*4/15 = 16/225 (Note that the expected outcome in this case is 4).
Probability of selecting 1 action movie = 6/15 = 2/5
<em>Hence, the probability that she selected 2 comedies and 1 action movie will be equivalent to 16/225*2/5 = 32/1125</em>
<em>Note that the rented movies will have to be returned hence reason for the replacement. </em>
I will try my best to assist you with your question ,
First we must divide the amount by 2
334/2 = 167
Now we add 16
167 + 16=183
So, the girl spent $183
Wow, she is spoiled!
Hope I helped!
Good Luck!
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
