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Neporo4naja [7]
3 years ago
6

Find the value of each variable.​

Mathematics
1 answer:
V125BC [204]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = \frac{\sqrt{3} }{2}, cos60° = \frac{1}{2}

sin45° = cos45° = \frac{1}{\sqrt{2} }

Using the sine ratio on the right triangle on the left

sin60° = \frac{opposite}{hypotenuse} = \frac{a}{4\sqrt{3} } = \frac{\sqrt{3} }{2}

Cross- multiply

2a = 4\sqrt{3} × \sqrt{3} = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = \frac{adjacent}{hypotenuse} = \frac{c}{4\sqrt{3} } = \frac{1}{2}

Cross- multiply

2c = 4\sqrt{3} ( divide both sides by 2 )

c = 2\sqrt{3}

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = \frac{a}{b} = \frac{6}{b} = \frac{1}{\sqrt{2} }

Cross- multiply

b = 6\sqrt{2}

cos45° = \frac{d}{b} = \frac{d}{6\sqrt{2} } = \frac{1}{\sqrt{2} }

Cross- multiply

\sqrt{2} d = 6\sqrt{2} ( divide both sides by \sqrt{2} )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6\sqrt{2}, c = 2\sqrt{3}, d = 6

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