Correct 24.3318 to two decimal places

How do i solve this??<br> 5x - 7 < 13

a_sh-v [17]

Answer:

5x-7 has to equal to something smaller than 13

5x-7=5

8 0

2 years ago

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Can someone help me with this?

Norma-Jean [14]

Answer:

the answer is d. ASA

BAC is congruent to DAC because its an angle bisector

AC is congruent to AC by the reflexive property of congruence

BCA is congruent to DCA because its a perpendicular bisector

4 0

3 years ago

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Shawna found coins worth $4.32. One- fourth of the found coins are pennies and one- sixth are quarters. The number of nickels fo

eduard

Answer:

8 quarters

12 nickels

12 pennies

16 dimes

Step-by-step explanation:

The trick is to ASSUME the dimes.

Start by thinking about the three explicit premises and the one implicit premise.

1) Quarters = 1/6 of total coins

2) Nickels = 1.5 the number of quarters

3) Pennies = 1/4 of total coins

Also, ASSUME an unknown number of dimes to fill in the gap.

48 Total Coins = $4.32

⅙ of 48 = 8 8 quarters = $2.00

1.5 x 8 = 12 12 nickels = $0.60

¼ of 48 = 12 12 pennies = $0.12

Add those coins = $2.72

Take the known total and minus this sum.

$4.32 - $2.72 = $1.60

16 dimes = $1.60

Thus, you have the following:

8 quarters (⅙ of total coins) $2.00

12 nickels (1.5 the number of quarters) $0.60

12 pennies (¼ the number of total coins) $0.12

+ 16 dimes $1.60

Total Coins 48 $4.32

8 0

3 years ago

How many terms are in 10y2-3y+8

Sergio [31]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to find how many terms are in $\pmb{10y^2-3y+8}$ .

$\triangle~\fbox{\bf{KEY:}}$

A term is a thing that's added or subtracted.

So let's compute the number of terms in this expression.

The first term is $\pmb{10y^2}$ .

Is anything added or subtracted from 10y²?

Sure! $\pmb{-3y}$ is subtracted from 10y².

Also, 8 is added to -3y.

Thus, this expression has 3 terms.

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

4 0

2 years ago

Use an appropriate Taylor series to find the first four nonzero terms of an infinite series that is equal to sin(5/2).

koban [17]

Answer:

2.5, -2.61, 0.81, -0.12

Step-by-step explanation:

The taylor series of the function sin(x) around zero is given by

$sin(x)=\sum_{n=0}^{\infty}\dfrac{(-1)^k}{(2k-1)!}x^{2k+1}=x-\dfrac{x^3}{3!}+\dfrac{x^5}{5!}-\dfrac{x^7}{7!}$

Therefore,

$\sin(\frac{5}{2})=\dfrac{5}{2}-\dfrac{[\frac{5}{2}]^3}{3!}+\dfrac{[\frac{5}{2}]^5}{5!}-\dfrac{[\frac{5}{2}]^7}{7!}+...$

hence the first four nonzero terms of the series are

$\dfrac{5}{2}=2.5\\\\-\dfrac{[\frac{5}{2}]^3}{3!} \approx -2.61\\\\\dfrac{[\frac{5}{2}]^5}{5!} \approx 0.81\\\\-\dfrac{[\frac{5}{2}]^7}{7!} \approx -0.12$

6 0

3 years ago